I have designed a gulp task for linting of .ts files present in my project. When I run it, it shows correct output on the prompt, but I am not sure how to redirect that output to a file so it can be printed so that I can handover the complete file to developer to correct the code accordingly.
my task looks like :
gulp.task('lint', function() {
gulp.src("src/**/**/*.ts")
.pipe(tslint({
formatter: "codeFrame",
configuration: "./tslint.json"
}))
.pipe(tslint.report({
configuration: {},
rulesDirectory: null,
emitError: true,
reportLimit: 0,
summarizeFailureOutput: true
}))
.pipe(gulp.dest('./Dest/reports'))
});
Could someone please suggest how do I achieve this.