I've a requirement to implement two keys in a dictionary and stuck a bit. I am not sure if it's possible to do but my criteria is to make a search option using two keys to match in a dictionary data structure similar to the below Linq:
if(id > 0 && status != null)
{
var result = (from c in db.Employees
where c.EmployeeId == id && c.Status == status
select c).ToList();
}
With Dictionary, I've tried the following:
public class Employee
{
public int EmployeeId { get; set; }
public string EmployeeName { get; set; }
public string Address { get; set; }
public string Status { get; set; }
}
public class TwoKeyDictionary<k1, k2, T> : Dictionary<k2, Dictionary<k2, T>>
{
}
Finally tried to the bind the Employee class with data and used List<> for that:
List<Employee> employees = new List<Employee>()
{
new Employee { EmployeeId = 1001, EmployeeName = "John", Address = "On Earth", Status = "Active"},
new Employee { EmployeeId = 1002, EmployeeName = "Jack", Address = "On Earth", Status = "Active"},
new Employee { EmployeeId = 1003, EmployeeName = "James", Address = "On Earth", Status = "Inactive"},
new Employee { EmployeeId = 1004, EmployeeName = "Oswald", Address = "On Earth", Status = "Inactive"}
};
int id = 0;
string status = ""
if (id > 0 && status != "")
{
id = Convert.ToInt32(Console.ReadLine())
status = Console.ReadLine().ToUpper();
}
TwoKeyDictionary<int, string, List<Employee>> dict =
employees.GroupBy(c => new {
CustomerId = c.EmployeeId,
c.Status })
.ToDictionary(g => g.Key.CustomerId, g => g.Key.Status, g => g.ToList());
foreach (var item in dict[id][status])
{
Console.WriteLine(item.CustomerId + " " + item.CustomerName);
}
It looks completed but right now, I am having exceptions and the one is: 'Cannot convert to lambda expression to type System.Collections.Generic.IEComparer because it is not a delegate type' - ToDictionary(g => g.Key.CustomerId, g => g.Key.Status, g => g.ToList(). The other error in this line: var item in dict[id][status]. Is there any way to get rid of it and may be doing the wrong thing somewhere.