How to write a range so that one of the values is left open to user input

Question

I would like to write a function for range where you enter a value when you are calling the function.

def randomRange():
    for num in range(0, ())
        print num

I would like the user to call the function like this "randomizeRange()"

And then I would like them to enter an integer to represent the maximum value in the range. I'm trying to get a better understanding of how to use the range function.

Also useful for understanding the range function are docs and tutorials, check out https://docs.python.org/3/library/functions.html#func-range , http://pythoncentral.io/pythons-range-function-explained/, etc. Google 'python range' — George Pantazes, Sep 28 '17 at 15:13

Alan Kavanagh · Answer 1 · 2017-09-28T15:19:00.087

3

You need to prompt the user for input using the input() or raw_input() methods and then convert this to an int()

Python 2:

def randomRange():
    for it in range(int(raw_input("How many loops?: "))):
        print it

Python 3:

def randomRange():
    for it in range(int(input("How many loops?: "))):
        print(it)

Example >input and >>output:

>>How many loops?:
> 2
>> 0
>> 1

edited Sep 28 '17 at 15:19

answered Sep 28 '17 at 15:11

Alan Kavanagh

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I agree that `input` is appropriate, but only in Python 3. the OP's code uses unparenthesized print, so he must be on Python 2.7 or lower, in which case he ought to use `raw_input` instead. – Kevin Sep 28 '17 at 15:12
1

It looks like the OP is using Python 2, so `raw_input` should be used. – Christian Dean Sep 28 '17 at 15:12
Updated the answer – Alan Kavanagh Sep 28 '17 at 15:29

How to write a range so that one of the values is left open to user input

1 Answers1