Need help in developing this code

Question

Assume s is a string of lower case characters.

Write a program that counts up the number of vowels contained in the string s. Valid vowels are: 'a', 'e', 'i', 'o', and 'u'. For example, if s = 'azcbobobegghakl', your program should print:

Number of vowels: 5

I came up with this code but I might be missing out on something I can't quite figure out yet

s = 'fddjhkloeavhkiyaeio'
vowels = ['a','e','i','o','u']
count = 0

for i in s:
    if i in vowels:
        count = count + 1
    print("Number of vowels: " , str(count))

this is the error Number of vowels: 8

* ERROR: Expected 6, got 8. *

Possible duplicate of [Count Vowels in String Python](https://stackoverflow.com/questions/19967001/count-vowels-in-string-python) — LW001, Sep 28 '17 at 18:43
whats the issue here. Do you get an error. If so please edit your question and add the exact error. — , Sep 28 '17 at 18:46
The `print` statement should be outside of the `for` loop, at the end. — eventHandler, Sep 28 '17 at 18:46
Why would you expect 6? There are 8 vowels in `fddjhkloeavhkiyaeio` — castis, Sep 28 '17 at 18:51
Also, consider adding your code in a function so that you can return the number of vowels — Dhiraj, Sep 28 '17 at 20:27

score 1 · Answer 1 · answered Sep 28 '17 at 18:55

You have a issue first pointed out by @castis above. Your print statement is in the wrong place. If you put it inside the for loop, it means that it will print every time the for loop iterates, so bring it back 2 indents. Like so:

s = 'fddjhkloeavhkiyaeio'
vowels = ['a','e','i','o','u']
count = 0

for i in s:
    if i in vowels:
        count = count + 1

print("Number of vowels: " , str(count))

Need help in developing this code

1 Answers1