Using the basics: Array Descending Order?

Question

Were now on arrays and the job is to do a list of numbers and then it would show the descending order of those numbers.

Here's the condition: A Nested Loop and a Decisive Structure.

I wasn't able to use this code:

for (iLoop = iNumber.length - 1; iLoop >= 0; iLoop--){
            System.out.println("" + iNumber[iLoop]);

Because it wouldn't show a nested loop one nor any decisive structures.

I can't use any sort of method YET. Only the first for loop will do the loop for the array. Here's my code next:

        int iX, iY, iLoop;
        Scanner var = new Scanner(System.in);
        int[]iNumber = new int [10];
        for (int iIndex = 0; iIndex < iNumber.length; iIndex++){
            System.out.print("Enter a number: ");
            iNumber [iIndex] = var.nextInt();
        }
        for (iX = 0; iX < iNumber.length; iX++){
            for (iY = iX + 1; iY < iNumber.length; iY++){
                if (iNumber[iX] < iNumber[iY]){
                    iLoop = iNumber[iX];
                    iNumber[iX] = iNumber[iY];
                    iNumber[iY] = iLoop;
                }
            }
        System.out.println("" + iNumber);
        }
    }
}

Now, I can't now think why the output is:

[I@1909752
[I@1909752
[I@1909752
[I@1909752
[I@1909752
[I@1909752
[I@1909752
[I@1909752
[I@1909752
[I@1909752

I don't know what to do again. Someone help me, thank you in advance.

You are sorting your numbers correctly (although inefficiently) but you are not printing them correctly. Look up "how to print an array in Java" and move `printf` out of the loop. — Sergey Kalinichenko, Sep 29 '17 at 11:10
I don't agree with the duplicate. It is not clear but OP need to print his array without add a loop or a method. Since this code is sorting is the opposite of a bubble sort (from the start to the end), this can be printed after each loop. — AxelH, Sep 29 '17 at 11:41

score 1 · Accepted Answer · answered Sep 29 '17 at 11:16

1

Print the iNumber[] array out of the loop :

for(int a : iNumber){
        System.out.println(a);
}

answered Sep 29 '17 at 11:16

Mohit Tyagi

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1

`Arrays.toString(iNumber)` is nice too ;) – AxelH Sep 29 '17 at 11:18
@AxelH yes, another way of printing array. – Mohit Tyagi Sep 29 '17 at 11:20
1

can you explain why did the `for` loop had a `:` inside it? – KenProgrammer Sep 29 '17 at 11:21
This character will list all the elements of the for loop – Mohit Tyagi Sep 29 '17 at 11:24
1

https://stackoverflow.com/questions/85190/how-does-the-java-for-each-loop-work – Mohit Tyagi Sep 29 '17 at 11:27
Thank you guys so much... all of you were helpful! – KenProgrammer Sep 29 '17 at 11:29
@KenProgrammer **Only the first for loop will do the loop for the array**. Your requirements is done to make you undestand the sort algorithm. You don't need/shouldn not use a other loop for that. **This is exactly the same thing as your loop posted in the question by the way...** The one you said "_I wasn't able to use this code:_" – AxelH Sep 29 '17 at 11:36

score 1 · Answer 2 · answered Sep 29 '17 at 11:25

Since you are sorting your array by setting the smallest value first into iNumber[iX] by iterating the elements after that point iY = iX + 1. You can simply print the iNumber[iX], each inner loop will set the correct value in that position

for (iX = 0; iX < iNumber.length; iX++){
    for (iY = iX + 1; iY < iNumber.length; iY++){
        if (iNumber[iX] < iNumber[iY]){
            iLoop = iNumber[iX];
            iNumber[iX] = iNumber[iY];
            iNumber[iY] = iLoop;
        }
     }
    System.out.println("" + iNumber[iX]); //Print the actual value
}

This will nicely print every value of iNumber[iX] after the loop setting his value.

Using the basics: Array Descending Order?

2 Answers2