Specifying startup window/form location on multiple displays

Question

I have two displays (two monitors) connected to my machine, and I noticed a strange thing happening today. I had an Explorer window open with my compiled exe on my primary display, and when I double-clicked it, it opened in the primary display (left monitor). However if I pressed enter to launch the executable, it started in the secondary display (right monitor). The window state of the initial form is maximized. Is there a way to tell C# to open the initial form in the primary display?

Thanks for the answers. Does anybody know what causes pressing enter vs double-clicking to result in diff behavior? — JeffE, Jan 10 '11 at 22:09

score 6 · Accepted Answer · answered Jan 10 '11 at 21:57

This should do the trick:

[STAThread]
static void Main()
{
    Application.EnableVisualStyles();
    Application.SetCompatibleTextRenderingDefault(false);

    Form1 f = new Form1();
    f.StartPosition = FormStartPosition.Manual;
    f.Location = Screen.PrimaryScreen.Bounds.Location;

    Application.Run(f);
}

score 1 · Answer 2 · edited May 23 '17 at 10:33

1

Take a look at this: Show form on primary or secondary screen

edited May 23 '17 at 10:33

Community

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answered Jan 10 '11 at 21:59

HABJAN

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score 0 · Answer 3 · answered Mar 09 '19 at 07:07

0

Screen[] myScreen = Screen.AllScreens;
this.Location = myScreen[0].WorkingArea.Location; // Primary Screen
this.Location = myScreen[1].WorkingArea.Location; // Secondary Screen

answered Mar 09 '19 at 07:07

Win Phay

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Please add some explanations with your code as well. – Partho63 Mar 09 '19 at 07:26

Specifying startup window/form location on multiple displays

3 Answers3

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