remove url parameters with javascript or jquery

Question

I am trying to use the youtube data api to generate a video playlist.

However, the video urls require a format of:

youtube.com/watch?v=3sZOD3xKL0Y

but what the api generates is:

youtube.com/watch?v=3sZOD3xKL0Y&amp;feature=youtube_gdata

So what I need to do is be able to select everything after and including the ampersand(&) and remove it from the url.

Any way to do this with javascript and some sort of regular expression?

Take a look at this post: http://stackoverflow.com/questions/738351/recommendation-for-javascript-url-manipulation-library-api/3215670#3215670 — HasanG, Sep 06 '11 at 23:21
possible duplicate of [querystring encoding of a javascript object](http://stackoverflow.com/questions/1714786/querystring-encoding-of-a-javascript-object) — Sindre Sorhus, Nov 15 '13 at 18:19

score 104 · Accepted Answer · answered Jan 04 '15 at 23:12

104

What am I missing?

Why not:

url.split('?')[0]

answered Jan 04 '15 at 23:12

Shining Love Star

5,734
5
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49

Works perfectly fine! – vishwarajanand Oct 29 '17 at 11:26
1

I'm wondering if there's a scenario in which this short solution doesn't work? – Shining Love Star Jul 02 '18 at 08:50
@goldylucks there is none, this is a perfectly adequate solution! – Oli C Sep 13 '19 at 16:47
3

exactly half a decade later, why isn't this the answer? – hellomello Jan 04 '20 at 23:29
I agree, this is way better than my juvenile answer from nearly a decade ago. – Jacob Relkin Feb 20 '20 at 08:11
It will also remove URI fragments if any, which may not be what you want. – Utsav Chatterjee Aug 19 '21 at 09:42

score 28 · Answer 2 · answered Jan 06 '14 at 09:15

28

Hmm... Looking for better way... here it is

var onlyUrl = window.location.href.replace(window.location.search,'');

answered Jan 06 '14 at 09:15

hriziya

1,116
1
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41

That's my specific case to reload the page without the parameters: window.location.assign(window.location.href.replace(window.location.search,'')); – gtamborero Nov 09 '17 at 12:39

score 25 · Answer 3 · answered Jan 10 '11 at 22:02

Example: http://jsfiddle.net/SjrqF/

var url = 'youtube.com/watch?v=3sZOD3xKL0Y&feature=youtube_gdata';

url = url.slice( 0, url.indexOf('&') );

or:

Example: http://jsfiddle.net/SjrqF/1/

var url = 'youtube.com/watch?v=3sZOD3xKL0Y&feature=youtube_gdata';

url = url.split( '&' )[0];

score 11 · Answer 4 · answered Aug 17 '17 at 12:17

Use this function:

var getCleanUrl = function(url) {
  return url.replace(/#.*$/, '').replace(/\?.*$/, '');
};

// get rid of hash and params
console.log(getCleanUrl('https://sidanmor.com/?firstname=idan&lastname=mor'));

If you want all the href parts, use this:

var url = document.createElement('a');
url.href = 'https://developer.mozilla.org/en-US/search?q=URL#search-results-close-container';

console.log(url.href); // https://developer.mozilla.org/en-US/search?q=URL#search-results-close-container
console.log(url.protocol); // https:
console.log(url.host); // developer.mozilla.org
console.log(url.hostname); // developer.mozilla.org
console.log(url.port); // (blank - https assumes port 443)
console.log(url.pathname); // /en-US/search
console.log(url.search); // ?q=URL
console.log(url.hash); // #search-results-close-container
console.log(url.origin); // https://developer.mozilla.org

score 6 · Answer 5 · answered Apr 21 '17 at 10:29

//user113716 code is working but i altered as below. it will work if your URL contain "?" mark or not
//replace URL in browser
if(window.location.href.indexOf("?") > -1) {
    var newUrl = refineUrl();
    window.history.pushState("object or string", "Title", "/"+newUrl );
}

function refineUrl()
{
    //get full url
    var url = window.location.href;
    //get url after/  
    var value = url = url.slice( 0, url.indexOf('?') );
    //get the part after before ?
    value  = value.replace('@System.Web.Configuration.WebConfigurationManager.AppSettings["BaseURL"]','');  
    return value;     
}

score 4 · Answer 6 · answered Feb 11 '19 at 21:10

4

This worked for me:

window.location.replace(window.location.pathname)

answered Feb 11 '19 at 21:10

Santiago Martí Olbrich

1,601
19
25

score 3 · Answer 7 · answered Feb 07 '21 at 18:37

No splits.. :) The correct/foolproof way is to let the native browser BUILT-IN functions do the heavy lifting using urlParams, the heavy lifting is done for you.

//summary answer - this one line will correctly replace in all current browsers
window.history.replaceState({}, '', `${location.pathname}?${params}`);

// 1 Get your URL 
let url = new URL('https://tykt.org?unicorn=1&printer=2&scanner=3');
console.log("URL: "+ url.toString());

// 2 get your params
let params = new URLSearchParams(url.search);
console.log("querys: " + params.toString());

// 3 Delete the printer param, Query string is now gone
params.delete('printer'); 
console.log("Printer Removed: " + params.toString()); 

// BELOW = Add it back to the URL, DONE!
___________

NOW Putting it all together in your live browser

// Above is a breakdown of how to get your params
// 4 then you simply replace those in your current browser!! 
window.history.replaceState({}, '', `${location.pathname}?${params}`);

Sample working Javascript Fiddle here

score 1 · Answer 8 · answered Jan 10 '11 at 22:02

1

You could use a RegEx to match the value of v and build the URL yourself since you know the URL is youtube.com/watch?v=...

http://jsfiddle.net/akURz/

var url = 'http://youtube.com/watch?v=3sZOD3xKL0Y';
alert(url.match(/v\=([a-z0-9]+)/i));

answered Jan 10 '11 at 22:02

Christian Joudrey

3,441
25
25

score 1 · Answer 9 · answered Jan 28 '18 at 01:41

Well, I am using this:

stripUrl(urlToStrip){
        let stripped = urlToStrip.split('?')[0];
        stripped = stripped.split('&')[0];
        stripped = stripped.split('#')[0];
        return stripped;
    }

or:

    stripUrl(urlToStrip){
        return urlToStrip.split('?')[0].split('&')[0].split('#')[0];
    }

score 0 · Answer 10 · answered Feb 11 '19 at 21:05

0

For example we have:

example.com/list/search?q=Somethink

And you need use variable url like this by window.location.href:

example.com/list/edit

From url:

example.com/list/search?q=Somethink
example.com/list/

var url = (window.location.href);
    url = url.split('/search')[0];
    url = (url + '/edit');

This is simple solution:-)

answered Feb 11 '19 at 21:05

Adrian

379
4
10

Please give an appropriate solution, this works only with /search patterns, what if i want to do these * values or say any value? – rohitcoder Feb 22 '21 at 14:04

remove url parameters with javascript or jquery

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