Interpreter says bad syntax, but I'm not being able to find the mistake

Question

print 'Welcome to the Pig Latin Translator!'

# Start coding here!
original = raw_input("Enter a word:")
if len(original) > 0 :
  print raw_input

  else:
    print "empty"

This is what interpreter says:

File "python", line 8
    else:
       ^
SyntaxError: invalid syntax

What am I doing wrong?

Your `else` needs to be indented in accordance with your `if`. — adder, Oct 02 '17 at 22:33
For clarity: indentation of `if` must match indentation of `else` — AJNeufeld, Oct 02 '17 at 22:37

Isaiah · Answer 1 · 2017-10-02T22:53:42.760

4

Your indentation for your else has to follow your if.

This is for Python in general, indentation matters.

print 'Welcome to the Pig Latin Translator!'

# Start coding here!

original = raw_input("Enter a word:")

if len(original) > 0:
    print raw_input

else:
    print "empty"

edited Oct 02 '17 at 22:53

answered Oct 02 '17 at 22:35

Isaiah

91
6

so, 4 spaces to each one, nothing else right? – gonza Oct 02 '17 at 22:41
4 spaces is good, but make sure its consistent per block – Isaiah Oct 02 '17 at 22:46
Each line from a block must have four spaces? or just else, and if? – gonza Oct 02 '17 at 22:50
Only indent what is in your `if` statement, and what is in your `else` statement. The actual lines with `if` and `else` don't need to be indented. I'll update my answer with code – Isaiah Oct 02 '17 at 22:52

Interpreter says bad syntax, but I'm not being able to find the mistake

1 Answers1