custom phone number regex

Question

I am using regex ^(\+91|[0]?)\d{10}$ for phone number validation. I want below output.

+911234567891 - valid
01234567891 - valid
1234567891 - valid
0123456789 - should be invalid as I want 10 digits after 0.

Please suggest changes in regex pattern Thanks in advance

Please add a language tag too bc regexes have different flavors in different languages. — Tamas Rev, Oct 04 '17 at 12:53
Something like [`^(?:(?:\+91|0)\d{10}|[1-9]\d{9})$`](https://regex101.com/r/sxowND/1)? — Wiktor Stribiżew, Oct 04 '17 at 12:54
Related: https://stackoverflow.com/questions/123559/a-comprehensive-regex-for-phone-number-validation?rq=1 — Jamiec, Oct 04 '17 at 12:56
@WiktorStribiżew : Thanks a ton ! It worked. Please post it as answer I will accept it. — user1829169, Oct 04 '17 at 12:59

score 3 · Accepted Answer · answered Oct 04 '17 at 13:02

Your ^(\+91|[0]?)\d{10}$ pattern matches +91 or an optional 0 and then any 10 digits. That means any 10 digit string will pass the test. You need to make sure 10 digits are allowed after +91 or 0, or make sure the first digit is 1 to 9 and the rest is just 9 digits.

You may use

^(?:(?:\+91|0)\d{10}|[1-9]\d{9})$

See the regex demo.

Details

^ - start of string
(?:(?:\+91|0)\d{10}|[1-9]\d{9}) - 2 alternatives:
- (?:\+91|0)\d{10} - +91 or 0 and then any 10 digits
- | - or
- [1-9]\d{9} - a digit from 1 to 9 and then any 9 digits
$ - end of string.

score 1 · Answer 2 · answered Oct 04 '17 at 13:05

1

Say for instance, in php - and javascript flavor you can use a possessive quantifier. Demo here. Code below:

^(\+91|0?+)\d{10}$

The change is replacing [0]? with 0?+. I removed the [...] for the sake of convenience. Then, the ?+ matches one 0 and won't let it go.

Another alternative is to list all the opportunities:

^(\+91\d{10}|0\d{10}|[1-9]\d{9})$

Demo here.

answered Oct 04 '17 at 13:05

Tamas Rev

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Thanks for the reply you guys are awesome, will surely try this one as well. – user1829169 Oct 05 '17 at 07:07

score 0 · Answer 3 · answered Oct 05 '17 at 06:00

0

Only mistake in your regex is a misplaced question mark.

^(\+91|0)?\d{10}$

You can remove the square bracket around '0' as it is a single character.

answered Oct 05 '17 at 06:00

soumya sunny

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So as per above answer what case can fail? – user1829169 Oct 05 '17 at 07:05
0123456789 will fail. Other 3 in your question will pass – soumya sunny Oct 05 '17 at 08:33
But I want this to fail – user1829169 Oct 06 '17 at 08:18

score 0 · Answer 4 · answered Apr 27 '20 at 18:35

0

/^([+]{0,1})([0]|[9][1]){0,1}([\d]{10})$/

answered Apr 27 '20 at 18:35

Gor Grigoryan

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While this code may answer the question, providing additional context regarding how and/or why it solves the problem would improve the answer's long-term value. – Donald Duck Nov 27 '20 at 12:26

custom phone number regex

4 Answers4