<?php
include"connect.php";
$name = $_REQUEST['name'];
$address = $_REQUEST['address'];
$password = $_REQUEST['password'];
$email = $_REQUEST['email'];
$number = $_REQUEST['number'];
$hear = $_REQUEST['hear'];
$money = $_REQUEST['money'];
$artist = $_REQUEST['artist'];
$security = $_REQUEST['security'];
$city = $_REQUEST['city'];
$pro = $_REQUEST['pro'];
$role = $_REQUEST['role'];
$accname = $_REQUEST['accname'];
$accpass = $_REQUEST['accpass'];
$accno = $_REQUEST['accno'];
$seaccname = $_REQUEST['seaccname'];
$seaccpass = $_REQUEST['seaccpass'];
$seaccno = $_REQUEST['seaccno'];
$contracts = $_REQUEST['contracts'];
$statements = $_REQUEST['statements'];
$result = mysqli_query($con, "insert into signup set name='$name',email='$email',password='$password' ,address='$address',cell_phone_number='$number',heard_from='$hear',money_time='$money',fav_artist='$artist',fav_city='$city',security_question='$security',pro='$pro',pro_acc_name='$accname',pro_acc_password='$accpass',pro_acc_number='$accno',se_acc_name='$seaccname',se_acc_pass='$seaccpass',se_ac_number='$seaccno',rec_contract_copy='$contracts',rec_label_copy='$statements',role='$role'");
//$result= mysqli_query($con, "INSERT INTO signup (name, email,password, address,cell_phone_number, heard_from,money_time, fav_artist,fav_city,security_question, pro,pro_acc_name, pro_acc_password,pro_acc_number, se_acc_name,se_acc_pass, se_ac_number,rec_contract_copy, rec_label_copy,role) VALUES ('$name', '$email', '$password', '$address', '$number', '$hear', '$money', '$artist', '$security', '$city', '$pro', '$role', '$accname', '$accpass', '$accno', '$seaccname', '$seaccpass', '$seaccno', '$contracts', '$statements')");
if($result==true)
{
//echo "<script>alert('user successfully added')</script>";
echo "Success";
}
else{
echo "Failed" ;
}
?>
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Funk Forty Niner
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check for the real errors then. If you don't know how, please ask. The connnection is unknown and if all `$_REQUEST`'s have value or not. – Funk Forty Niner Oct 04 '17 at 18:13
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what's the output of mysqli_error($con)? – LordNeo Oct 04 '17 at 18:15
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2Your code is vulnerable to [**SQL injection**](https://en.wikipedia.org/wiki/SQL_injection) attacks. You should use prepared statements with bound parameters, via either the [**mysqli**](https://secure.php.net/manual/en/mysqli.prepare.php) or [**PDO**](https://secure.php.net/manual/en/pdo.prepared-statements.php) drivers. [**This post**](https://stackoverflow.com/questions/60174/how-can-i-prevent-sql-injection-in-php) has some good examples. – Alex Howansky Oct 04 '17 at 18:16
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i have three forms on the same page but on different slides with the button to move from one page to another and in the last a finish button to submit the data and send to the database but its not working and displaying failed by echo in this code, and i am using ajax for that. – Yash Singhal Oct 05 '17 at 02:21
2 Answers
0
It won't run because your query is wrong, you are using insert statement with update format.
$result= mysqli_query($con, "INSERT INTO signup (name, email,password, address,cell_phone_number, heard_from,money_time, fav_artist,fav_city,security_question, pro,pro_acc_name, pro_acc_password,pro_acc_number, se_acc_name,se_acc_pass, se_ac_number,rec_contract_copy, rec_label_copy,role) VALUES ('$name', '$email', '$password', '$address', '$number', '$hear', '$money', '$artist', '$security', '$city', '$pro', '$role', '$accname', '$accpass', '$accno', '$seaccname', '$seaccpass', '$seaccno', '$contracts', '$statements')");
and further info, Start using Prepared Statement PDO

Aniket Singh
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0
It looks ok. Problem could be in connect.php or the names in $_REQUEST are not the same as in file where request is sent. Also check that names of atributes in database you are inserting into match those in query.

Ana
- 11
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