Python - Using while loops in functions

Question

I'm trying to create a function that uses a while loop to count up from one to a number given by a user. The code executes as I intend it to but returns None at the end. How do I get rid of the None? Here's the code.

def printFunction(n):
    i = 1
    while i <= n:
        print(i)
        i+=1


print (printFunction(int(input())))

Replace `print (printFunction(int(input()))` with `printFunction(int(input())` - don't print the return value if there's nothing being returned. — cs95, Oct 04 '17 at 21:41
If you don’t want to see None, don’t print the return value of a function that doesn’t return anything? — jonrsharpe, Oct 04 '17 at 21:41

score 1 · Accepted Answer · edited Oct 04 '17 at 21:56

1

You can use this code to prevent none, tough its just the last line changed

def printFunction(n):
i = 1
while i <= n:
    print(i)
    i+=1
printFunction(int(input()))

In the last line you were using print(printFunction(int(input()))) which was getting you None after printing the results.

Instead just use printFunction(int(input())). This will not print None. You can also use a message to ask user like printFunction(int(input("Enter a number"))). Since there is noting getting returned you no need to use print.

edited Oct 04 '17 at 21:56

tobias_k

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answered Oct 04 '17 at 21:46

Chetan_Vasudevan

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`printFunction` is the name of the function. `Function` is not defined. – tobias_k Oct 04 '17 at 21:47
1

...did you read the question? – cs95 Oct 04 '17 at 21:47

Python - Using while loops in functions

1 Answers1