how to get what number is the letter in the word?

Question

I have this program:

word = input('enter word:')
letter = input('enter letter to find:')

y = word.find(letter)
print(y)

and it only print 0:

enter word:pythop
enter letter to find:p
0
>>>

so how can I get the position of both of this letter 'p' as it only recognise one of it? thanks

You've already got it. `y` is the index. `find()` function finds the first match. — Alperen, Oct 05 '17 at 14:31

score 2 · Answer 1 · answered Oct 05 '17 at 14:29

2

You got it! String position 0 is the first position in a string.

>>> 'pythop'.find('p')
0
>>> 'pythop'.find('y')
1
>>>

answered Oct 05 '17 at 14:29

Mike N

6,395
4
24
21

yes...but there are two p's there and it only recognises one...so how can I get both of it? – Joe han Oct 05 '17 at 14:39

magnusnn · Answer 2 · 2017-10-05T15:02:39.140

1

Updated my answer due to typo:

I would do something like this:

word = input('enter word:')
letter = input('enter letter to find:')

y = [i for i in range(len(word)) if word.startswith(letter, i)]
print(y)

Hope this helps

edited Oct 05 '17 at 15:02

answered Oct 05 '17 at 14:57

magnusnn

137
1
13

yeah..it helps..thanks – Joe han Oct 05 '17 at 15:15

score 1 · Accepted Answer · answered Oct 05 '17 at 15:08

You do need a loop. If you only ever need to check for a single letter (not a substring), you can enumerate the characters of the word:

word = input('enter word:')
letter = input('enter letter to find:')

ys = [i for i, l in enumerate(word) if l == letter]
print(ys)

score 0 · Answer 4 · answered Oct 05 '17 at 15:01

You can use find with start and end positions. Here the docstring:

find(...)
    S.find(sub [,start [,end]]) -> int

    Return the lowest index in S where substring sub is found,
    such that sub is contained within S[start:end].  Optional
    arguments start and end are interpreted as in slice notation.

    Return -1 on failure.

how to get what number is the letter in the word?

4 Answers4