EDIT
I have implemented the changes suggested and I still cant get this to work:
Form Page Follows (login.php)
<?php
$mac=$_POST['mac'];
$ip=$_POST['ip'];
$username=$_POST['username'];
$linklogin=$_POST['link-login'];
$linkorig=$_POST['link-orig'];
$error=$_POST['error'];
$chapid=$_POST['chap-id'];
$chapchallenge=$_POST['chap-challenge'];
$linkloginonly=$_POST['link-login-only'];
$linkorigesc=$_POST['link-orig-esc'];
$macesc=$_POST['mac-esc'];
if (isset($_POST['postcode'])) {
$postcode = $_POST['postcode'];
}
if (isset($_POST['email'])) {
$email = $_POST['email'];
}
?>
**SOME HTML HERE**
<script src="jquery-3.2.1.min.js"></script>
<script>
var js-postcode = document.login.getElementsByName("postcode").value;
var js-email = document.login.getElementsByName("email").value;
var formdata = {postcode:js-postcode,email:js-email};
$("button").click(function(){
$.ajax(
{
type: "POST",
url: "database.php", //Should probably echo true or false depending if it could do it
data : formdata,
success: function(feed) {
if (feed!="true") {
// DO STUFF
} else {
console.log(feed);
// WARNING THAT IT WASN'T DONE
}
}}}
</script>
</head>
<body>
<table width="100%" style="margin-top: 10%;">
<tr>
<td align="center" valign="middle">
<table width="240" height="240" style="border: 1px solid #cccccc; padding: 0px;" cellpadding="0" cellspacing="0">
<tr>
<td align="center" valign="bottom" height="175" colspan="2">
<!-- removed $(if chap-id) $(endif) around OnSubmit -->
<form name="login" action="<?php echo $linkloginonly; ?>" method="post" onSubmit="return doLogin()" >
<input type="hidden" name="dst" value="<?php echo $linkorig; ?>" />
<input type="hidden" name="popup" value="true" />
<table width="100" style="background-color: #ffffff">
<tr><td align="right">login</td>
<td><input style="width: 80px" name="username" type="text" value="<?php echo $username; ?>"/></td>
</tr>
<tr><td align="right">password</td>
<td><input style="width: 80px" name="password" type="password"/></td>
</tr>
<tr><td align="right">Postcode</td>
<td><input style="width: 80px" name="postcode" type="text" /></td>
</tr>
<tr><td align="right">Email</td>
<td><input style="width: 80px" name="email" type="text" /></td>
</tr>
<td><button><input type="submit" value="OK" /></button></td>
</tr>
</table>
</form>
</td>
</tr>
</table>
</td>
</tr>
</table>
<script type="text/javascript">
<!--
document.login.username.focus();
//-->
</script>
</body>
</html>
and called file database.php is as follows:
<?php
if ((isset($_POST['postcode'])) && (isset($_POST['email']))) {
$postcode = $_POST['postcode'];
$email = $_POST['email'];
$connect= new mysqli_connect('xx','xx','xx','xx');
if ($conn->connect_errno) {
echo "There was a problem connecting to MySQL: (" . $conn->connect_errno . ") " . $conn->connect_error;
}
if (!($sql = $conn->prepare("INSERT INTO visitors(postcode,email) VALUES(postcode,email)"))) {
echo "Prepare failed: (" . $conn->errno . ") " . $conn->error;
}
//NOTE: the "ss" part means that $postcode and $email are strings (mysql is expecting datatypes of strings). For example, if $postcode is an integer, you would do "is" instead.
if (!$sql->bind_param("ss", $postcode, $email)) {
echo "Binding parameters failed: (" . $sql->errno . ") " . $sql->error;
}
if (!$sql->execute()) {
echo "Execute failed: (" . $sql->errno . ") " . $sql->error;
}
} else {
echo 'Variables did not send through ajax.'; // any echoed values would be sent back to javascript and stored in the 'response' variable of your success or fail functions for testing.
}
?>
Still I get nothing fed through from the form to the database. Even if I swap the variables for strings I get nothing through to the database however if I run database.php separately it works. Surely Im close to getting this working now .. any help appreciated and thanks so much for the assistance provided so far.
*************************** ORIGINAL QUESTION FOLLOWS *******************
I have a simple form as follows:
<form name="login" action="somethingelse.php" method="post" onSubmit="return doLogin()" >
<input type="hidden" name="dst" value="<?php echo $linkorig; ?>" />
<input type="hidden" name="popup" value="true" />
<table width="100" style="background-color: #ffffff">
<tr><td align="right">login</td>
<td><input style="width: 80px" name="username" type="text" value="<?php e$
</tr>
<tr><td align="right">password</td>
<td><input style="width: 80px" name="password" type="password"/></td>
</tr>
<tr><td align="right">Postcode</td>
<td><input style="width: 80px" name="postcode" type="text" /></td>
</tr>
<tr><td align="right">Email</td>
<td><input style="width: 80px" name="email" type="text" /></td>
</tr>
<td><button><input type="submit" value="OK" /></button></td>
</tr>
</table>
</form>
Because I need to use the form action to do something else, I need to use jQuery on the click of the button to send data to a database. Specifically the postcode and email address taken from the form. The part of the code relating to the jQuery is shown below:
<script language="JavaScript" >
$(document).ready(function(){
$("button").click(function(){
mysqli_query();
});
});
</script>
The called function mysqli_query is declared via an include statement and therefore lives in a different file. The function called is shown below:
mysqli_query( $connect, "INSERT INTO visitors(postcode,email) VALUES(postcode,email)");
I have been going round in circles for days with this. I know Im close to making it work but cant quite cross the finish line. Could somebody please point out what I'm doing wrong here?
