How to see traceback on xmlrpc server, not client?

Question

I have simple xmlrpc server code:

from SimpleXMLRPCServer import SimpleXMLRPCServer

port = 9999

def func():
    print 'Hi!'
    print x # error!
    print 'Bye!'

if __name__ == '__main__':
    server = SimpleXMLRPCServer(("localhost", port))
    print "Listening on port %s..." % port
    server.register_function(func)
    server.serve_forever()

Sample session.

Client:

>>> import xmlrpclib
>>> p = xmlrpclib.ServerProxy('http://localhost:9999')
>>> p.func()
Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
  File "C:\Python26\lib\xmlrpclib.py", line 1199, in __call__
    return self.__send(self.__name, args)
  File "C:\Python26\lib\xmlrpclib.py", line 1489, in __request
    verbose=self.__verbose
  File "C:\Python26\lib\xmlrpclib.py", line 1253, in request
    return self._parse_response(h.getfile(), sock)
  File "C:\Python26\lib\xmlrpclib.py", line 1392, in _parse_response
    return u.close()
  File "C:\Python26\lib\xmlrpclib.py", line 838, in close
    raise Fault(**self._stack[0])
xmlrpclib.Fault: <Fault 1: "<type 'exceptions.NameError'>:global name 'x' is not defined">
>>>

Server:

Listening on port 9999...
Hi!
localhost - - [11/Jan/2011 16:17:09] "POST /RPC2 HTTP/1.0" 200 -

The question is if I can get this trace back also on server. I need to know if something went wrong with processing query. I'm not using client written in Python so it is hard for me to get traceback like above.

Your question is really confusing. You say you're not using a client in python, but your client is python code. — Falmarri, Jan 11 '11 at 16:02
Yes, but that is just example. As client I'm using some dll which base on xmlrpc-c library. And I really don't want to change code of this dll... — Adam, Jan 11 '11 at 16:18

mouad · Accepted Answer · 2012-03-12T18:22:35.160

You can do something like this:

from SimpleXMLRPCServer import SimpleXMLRPCServer, SimpleXMLRPCRequestHandler

port = 9999

def func():
    print 'Hi!'
    print x # error!
    print 'Bye!'

class Handler(SimpleXMLRPCRequestHandler):
     def _dispatch(self, method, params):
         try: 
             return self.server.funcs[method](*params)
         except:
             import traceback
             traceback.print_exc()
             raise


if __name__ == '__main__':
    server = SimpleXMLRPCServer(("localhost", port), Handler)
    server.register_function(func)
    print "Listening on port %s..." % port
    server.serve_forever()

Traceback server side:

Listening on port 9999...
Hi!
Traceback (most recent call last):
  File "xml.py", line 13, in _dispatch
    value = self.server.funcs[method](*params)
  File "xml.py", line 7, in func
    print x # error!
NameError: global name 'x' is not defined
localhost - - [11/Jan/2011 17:13:16] "POST /RPC2 HTTP/1.0" 200

should explicitly use requestHandler keyword, `SimpleXMLRPCServer(("localhost", port), requestHandler=Handler)` — Ciasto piekarz, Jul 20 '18 at 07:53

How to see traceback on xmlrpc server, not client?

1 Answers1