How to open particular activity of 3rd party application

Question

I know I can open Activity with Intent but I am trying to open particular Activity from my application.

Intent launchIntent = getPackageManager().getLaunchIntentForPackage("com.3rdPartyApplcation");
if (launchIntent != null) 
{
     startActivity(launchIntent);
}

Example:- My application is A I have to open Settings page of Application B which is 3rd party application, I also know the activity name.

How to open this settings page via intent

solution https://stackoverflow.com/a/2210073/1872098 and third party app activity must have exported = true in manifest — Ravi Kant, Oct 06 '17 at 12:51
Most likely, that activity is not exported, and therefore you cannot start it. — CommonsWare, Oct 06 '17 at 12:51
java.lang.SecurityException: Permission Denial: starting Intent I also added android:exported="true" — Akshay Katariya, Oct 06 '17 at 13:20

score 1 · Answer 1 · answered Oct 06 '17 at 12:48

1

First you need to find out the package name of the app u want to launch using intent along with the activity name which u want to launch directly from your app.

 Intent intent=new Intent();
 intent.setComponent(new ComponentName("com.3rdPartyApplcation.packagename", "com.3rdPartyApplcation.packagename.SettingsActivity"));
 startActivity(intent);

answered Oct 06 '17 at 12:48

Akshay Chopde

670
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10

java.lang.SecurityException: Permission Denial: starting Intent I also added android:exported="true" – Akshay Katariya Oct 06 '17 at 13:20
The activity which u launch must be declared as android:exported="true" in manifest.xml. Otherwise u got the exception – Akshay Chopde Oct 06 '17 at 15:04

How to open particular activity of 3rd party application

1 Answers1