How to check dates basing on year and month in Python

Question

I'd like to check the days for a given month . For an instance, if I input year 2017 and month 2 or February , I would like to receive all dates for that month, in this case 01-28.02.2017.

Is it possible to do in Python? Was trying to find something using google, but unsuccessfully.

Thanks in advance,

Possible duplicate of [Get Last Day of the Month in Python](https://stackoverflow.com/questions/42950/get-last-day-of-the-month-in-python) — bgfvdu3w, Oct 08 '17 at 08:35
Every month starts with day 1. If you know the first day and the last, then you also know everything between. — bgfvdu3w, Oct 08 '17 at 08:39

Delgan · Accepted Answer · 2017-10-08T08:43:17.410

3

There is a function for this in the standard library: itermonthdates().

from calendar import Calendar

for date in Calendar().itermonthdates(2017, 2):
    print(date)

You may need to filter the dates with if date.month == 2, because it will contain days from the previous and next months if they belong to the same week.

edited Oct 08 '17 at 08:43

answered Oct 08 '17 at 08:35

Delgan

18,571
11
90
141

Does this take leap years into account? – Oct 08 '17 at 08:42
@mikey yes, it does. – Adam Smith Oct 08 '17 at 08:47
so `for date in (d for d in Calendar().itermonthdates(2017, 2) if d.month == 2)` – Adam Smith Oct 08 '17 at 08:48

score 1 · Answer 2 · answered Oct 08 '17 at 08:53

Alternative, as Mark suggested in the comments, if you know the month then you can do this yourself.

import calendar

year, month = 2017, 2

def days_in_month(date):
    if calendar.isleap(date.year) and date.month == 2:
        return 29
    else:
        return [None, 31, 28, 31, 30, 31, 30, ...][date.month]

date = datetime.date(year=year, month=month)

dates = [datetime.date(year=year, month=month, day=d) for d in range(1, days_in_month(date)+1)]

How to check dates basing on year and month in Python

2 Answers2