Order Swift array by two fields

Question

I have this problem. I have this vector with two fields for position:

fecha:  9/10/2017
turno:  0
fecha:  9/10/2017
turno:  6
fecha:  9/10/2017
turno:  17
fecha:  10/10/2017
turno:  17

And for order this I am using this code:

self.TodasMisCitas.sort {
    if ($0.fecha as Date == $1.fecha as Date) {
        return ($0.turno) > ($1.turno)
    }
    return ($0.fecha) > ($1.fecha)
}

This is the output:

i don't upload image :( see in this link please

The correct output for me will be:

martes 10/10/2017
lunes 09/10/2017 a las 10:00
lunes 09/10/2017 a las 11:30
lunes 09/10/2017 a las 16:00

Anybody know what's happening?

When you compare the dates with == maybe you should take into account the day not the entire date. — TomCobo, Oct 08 '17 at 16:15
Explain what is exactly `fecha`. Your code should work, but if `fecha` doesn't hold hours/minutes (while a `Date` object does), but just the day it won't. And you mean that if the day/hour/minute are the same, then you check the `turno`, right? — Larme, Oct 08 '17 at 16:30

score 0 · Accepted Answer · answered Oct 08 '17 at 16:21

When you compare the dates with == maybe you should take into account the day not the entire date. I couldn't compile but I think it should be something like this:

self.TodasMisCitas.sort {
    if Calendar.current.compare($0.fecha, to: $1.fecha, toGranularity: .day) == .orderedSame {
        return ($0.turno) > ($1.turno)
    }
    return ($0.fecha) > ($1.fecha)
}

Order Swift array by two fields

1 Answers1