I need to achieve this:
def x():
subprocess.Popen(...)
I cannot modify x() however I need to reach (suppress) stderr / stdout of the Popen call inside.
I need something like:
with suppress_subprocess:
x()
...or something like that.
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vpas
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https://stackoverflow.com/questions/10683184/piping-popen-stderr-and-stdout – uspectaculum Oct 08 '17 at 15:35
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Have a look at python decorators @vpas – Raju Pitta Oct 08 '17 at 15:37
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Please give me more help, and please note the inside of x() function cannot be modified! – vpas Oct 08 '17 at 15:41
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Is it cheating to alter `x`'s globals to find another `subprocess`? – Davis Herring Oct 08 '17 at 16:44
3 Answers
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return from your x function the popen object and then just access him from your caller file like so:
def x():
return subprocess.Popen(...)
p= x()
print p.stdout
print p.stderr
print p.returncode
etc ....
ddor254
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As I said: x() function cannot be modified, let's say it's 3rd party code. – vpas Oct 08 '17 at 15:53
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There is no direct and easy way. You would have to determine the PID of the subprocess and mess with its UNIX file descriptors, from another thread. Messy.
Chris Johnson
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By the time you could find the PID, it's too late: you're racing with its (first) output. – Davis Herring Oct 08 '17 at 16:45
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Sine
... I need to reach (suppress)
stderr/stdout...
have you tried the approach described here Silence the stdout of a function in Python without trashing sys.stdout and restoring each function call?
In your case it can be something like
import io
import sys
save_stdout = sys.stdout
suppress_stdout():
try:
sys.stdout = io.BytesIO()
x()
finally:
sys.stdout = save_stdout
Dušan Maďar
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