how to pass argv parameters in GUI program c++, not console?

Question

folks.

i want pass argv parameters in my GUI program which written c++, my program is not the black screen console, but it is a GUI. for example my program is AAA.exe, and i want to pass a command like "AAA.exe doThing" etc. how can i do it? thank you all so much.

[WinMain: The Application Entry Point](https://msdn.microsoft.com/en-us/library/windows/desktop/ff381406(v=vs.85).aspx) — zdf, Oct 10 '17 at 03:35
Pass them in exactly the same way. Perhaps your question is how to read them. — David Heffernan, Oct 10 '17 at 07:19

Dúthomhas · Answer 1 · 2021-01-09T05:14:20.073

3

While WinMain is the application entry point, it does not help you very much with command line arguments.

(You can get the command line from anywhere using GetCommandLine().)

You can parse it using CommandLineToArgvW().

edited Jan 09 '21 at 05:14

answered Oct 10 '17 at 04:00

Dúthomhas

8,200
2
17
39

thank you, i got it and came up following answers. i have tested it, working as arrow... – Aqtemir Oct 10 '17 at 04:45

score 1 · Answer 2 · edited Oct 11 '17 at 10:01

1

If you use VS you can easily use __argc and __argv.

These variables are automatically populated by the CRT. The variables are available in an MBCS/ANSI version and an Unicode version. __argv is the MBCS/ANSI version, whereas __wargv is the unicode version.

To use them we have just to include stdlib.h. there is also a __targv version available when you include TCHAR.h.

edited Oct 11 '17 at 10:01

IInspectable

46,945
8
85
181

answered Oct 10 '17 at 06:17

xMRi

14,982
3
26
59

There is no ASCII version. There is an ANSI version, tough. – IInspectable Oct 10 '17 at 07:09
You are right! I corrected my answer. – xMRi Oct 10 '17 at 07:14
You still have "_argv is the ascii version_". – zett42 Oct 10 '17 at 10:37
Changed it again! – xMRi Oct 10 '17 at 10:39
"__arcg" is a typo. It should be __argc, of course. – Eryk Sun Oct 10 '17 at 14:07

score -2 · Answer 3 · answered Oct 10 '17 at 04:48

-2

came up with following answers, it was tested and working nicely as arrow. added this code in WinMain block.

LPWSTR *szArgList;
int argCount;

 szArgList = CommandLineToArgvW((LPWSTR)GetCommandLine(), &argCount);
 if (szArgList == NULL){
     MessageBox(NULL, "Unable to parse command line", "Error", MB_OK);
     return 10;
 }
 int wint = 1;
 for(int i = 0; i < argCount; i++){
    cout << "szArgList[i]: " << (LPSTR)szArgList[i] << endl;
    string argsbek= (LPSTR)szArgList[i];
    if (argsbek.find(" passMyword") != string::npos){
       cout <<"words are passed ..."<<endl;
       wint=2;
    }
 }
 LocalFree(szArgList);

answered Oct 10 '17 at 04:48

Aqtemir

1
1
5

3

The casts will surely silence the compiler. But once you run the program, you'll see that it fails. Use `GetCommandLineW()` and `wcout`, and drop the casts. You should probably also remove all the unrelated code. – IInspectable Oct 10 '17 at 07:12
Nope, this code is no good. – David Heffernan Oct 10 '17 at 07:23
Great, thank you very much. – Aqtemir Oct 10 '17 at 10:21

how to pass argv parameters in GUI program c++, not console?

3 Answers3