How to split a specific string after in java

Question

I have the following string:

String result = "@sequence@A:exampleA@B:exampleB";

I would like to split this string into two strings like this:

String resulta = "sequence";

String resultb = "@A:exampleA@B:exampleB";

How can I do this? I'm new to Java programming language.

Thanks!

you want to skip and remove @ only in first part but 2nd part shall contain @? — Optional, Oct 10 '17 at 07:06
Can you explain the rule(s) you followed to get to your desired result? Or maybe provide some more examples? — Felk, Oct 10 '17 at 07:08
@Felk I just want to split this string into two parts. In the first one I want to express the word without "@" and in the second rest of string. Good? :) — Kima321, Oct 10 '17 at 07:19

Optional · Accepted Answer · 2017-10-10T07:18:25.450

0

if you want typical split, (Specific to your string), you can call substring and get the part of it like below:

     String s = "@sequence@A:exampleA@B:exampleB";
        String s1= s.substring(1,s.indexOf("@",1));
        System.out.println(s1);
        String s2= s.substring(s1.length()+1);
        System.out.println(s2);
     }

Edit as per your comment

String s3= s.substring(s.indexOf("@",1));
System.out.println(s3);

edited Oct 10 '17 at 07:18

answered Oct 10 '17 at 07:11

Optional

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Thanks very much :) But can you get "s2" only with main "s" variables? – Kima321 Oct 10 '17 at 07:16
@Kima321 Edited answer as per your comment using only s. In s1, we are doing substring till 2nd @. In s3, we are doing substring "from" 2nd @ – Optional Oct 10 '17 at 07:19

score 0 · Answer 2 · 2017-10-10T07:27:00.293

0

String result = "@sequence@A:exampleA@B:exampleB";

if(result.indexOf("@") == 0)
    result = result.substring(1, result.length());

String resultA = result.substring(0, result.indexOf("@"));
String resultB = result.substring(resultA.length(), result.length());

edited Oct 10 '17 at 07:27

answered Oct 10 '17 at 07:15

this will not give the op the 2nd string with @. – Optional Oct 10 '17 at 07:17

score 0 · Answer 3 · answered Oct 10 '17 at 07:18

Try,

    String result = "@sequence@A:exampleA@B:exampleB", resulta, resultb;
    int splitPoint = result.indexOf('@',1);
    resulta = result.substring(1, splitPoint);
    resultb = result.substring(splitPoint);

    System.out.println(resulta+", "+resultb);

How to split a specific string after in java

3 Answers3