Convert Array to List in Kotlin

Question

I try to do this with (same as java)

val disabledNos = intArrayOf(1, 2, 3, 4)
var integers = Arrays.asList(disabledNos)

but this doesn't give me a list. Any ideas?

The main problem why it didn't work in the first place, was, that you basically created a `List`. You need to use the [spread operator (`*`)](https://kotlinlang.org/docs/reference/functions.html#variable-number-of-arguments-varargs) to get a `List`, i.e. the following would have worked too: `val integers = Arrays.asList(*disabledNos)`. A similar question, that also mentions the actual error: [Convert `Array` to `ArrayList`](https://stackoverflow.com/questions/55451118/convert-arraystring-to-arrayliststring) — Roland, Apr 01 '19 at 09:29

score 99 · Accepted Answer · answered Oct 10 '17 at 09:12

99

Kotlin support in the standard library this conversion.

You can use directly

disableNos.toList()

or if you want to make it mutable:

disableNos.toMutableList()

answered Oct 10 '17 at 09:12

crgarridos

Alok Gupta · Answer 2 · 2020-05-29T06:51:26.167

2

This will fix your problem :

val disabledNos = intArrayOf(1, 2, 3, 4)
var integers = Arrays.asList(*disabledNos)

Just add * to this to asList

edited May 29 '20 at 06:51

answered Mar 26 '20 at 05:43

Alok Gupta

score 0 · Answer 3 · edited Jun 29 '18 at 09:03

0

Oops that was very simple:

var integers = disabledNos.toList()

edited Jun 29 '18 at 09:03

Jake Lee

answered Oct 10 '17 at 09:05

Adolf Dsilva

2

This will give you `List` instead of `List`. @crgarridos's answer is correct. – BakaWaii Oct 10 '17 at 15:33
Oh boy I forgot to remove Arrays.asList() while posting the answer :( – Adolf Dsilva Oct 11 '17 at 08:00

3 Answers3