How to check if array contains at least one object ?

Question

I want to check if array contains object or not. I am not trying to compare values just want to check in my array if object is present or not?

Ex.

$arr = ['a','b','c'] // normal
$arr = [{ id: 1}, {id: 2}] // array of objects
$arr = [{id: 1}, {id:2}, 'a', 'b'] // mix values

So how can i check if array contains object

Loop through array items and test if it's object https://stackoverflow.com/questions/8511281/check-if-a-value-is-an-object-in-javascript — Zamrony P. Juhara, Oct 10 '17 at 09:40
Are you looking for a specific value, or just if the array contains "any object"? — Cerbrus, Oct 10 '17 at 09:42

Mihai Alexandru-Ionut · Accepted Answer · 2017-10-10T10:36:29.180

24

You can use some method which tests whether at least one element in the array passes the test implemented by the provided function.

let arr = [{id: 1}, {id:2}, 'a', 'b'];
let exists = arr.some(a => typeof a == 'object');
console.log(exists);

edited Oct 10 '17 at 10:36

answered Oct 10 '17 at 09:40

Mihai Alexandru-Ionut

47,092
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@parth, `some` method provide a callback test function for ever item from the array. The `test` function check if array item is object. The `condition` is if `typeof a` is object.`some` method returns true if `at least` one item from the array satifiy the condition. – Mihai Alexandru-Ionut Oct 10 '17 at 10:36

score 5 · Answer 2 · answered Oct 10 '17 at 09:39

5

I want to check if array contains object or not

Use some to simply check if any item of the array has value of type "object"

var hasObject = $arr.some( function(val){
   return typeof val == "object";
});

answered Oct 10 '17 at 09:39

gurvinder372

66,980
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score 1 · Answer 3 · answered Oct 10 '17 at 09:50

var hasObject = function(arr) {
  for (var i=0; i<arr.length; i++) {
    if (typeof arr[i] == 'object') {
      return true;
    }
  }
  return false;
};

console.log(hasObject(['a','b','c']));
console.log(hasObject([{ id: 1}, {id: 2}]));
console.log(hasObject([{id: 1}, {id:2}, 'a', 'b']));

score 0 · Answer 4 · answered Oct 10 '17 at 09:47

You could count the objects and use it for one of the three types to return.

function getType(array) {
    var count = array.reduce(function (r, a) {
        return r + (typeof a === 'object');
    }, 0);
    
    return count === array.length
        ? 'array of objects'
        : count
            ? 'mix values'
            : 'normal';
}

console.log([
    ['a', 'b', 'c'],
    [{ id: 1 }, { id: 2 }],
    [{ id: 1 }, { id: 2 }, 'a', 'b']
].map(getType));

score 0 · Answer 5 · answered Sep 05 '18 at 22:29

0

With a type check on array

const hasObject = a => Array.isArray(a) && a.some(val => typeof val === 'object')

answered Sep 05 '18 at 22:29

Gorky

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How to check if array contains at least one object ?

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