Not able to open a file using python

Question

I'm trying to open a file using this code but it is again and again showing the error: NameError: name "practice" is not defined where "practice" is the name of the file which I'm trying to open. "practice.txt" (the file that im trying to open) is present in the same directory in which my python program has been created.

import os
name = input("Enter the name of the file : ") 
if(os.path.exist(name)==True):
    fopen = open(name,'w')
    line = fopen.readline()
    while(line != ""):
        print(line)
        line=fopen.readline()
    fopen.close()
else:
    print("file does not exist!!!")

Based on your error message, you should be using `raw_input` — Wondercricket, Oct 12 '17 at 14:24

score 0 · Answer 1 · answered Oct 12 '17 at 14:26

0

This is because you must specify the PATH of the file as well as the filename.

I.E. open("Files/images/Image1.png", "MODE")

answered Oct 12 '17 at 14:26

EgMusic

136
17

If the file is in the same directory, the path is not needed – Wondercricket Oct 12 '17 at 16:16
True, @Wondercricket, but you need the file extension as well. Maybe that's what he forgot. – EgMusic Oct 12 '17 at 16:47
I didn't forget the extension. I am writing the file name alongwith the extension ".txt" @EgMusic – Anant Vikram Singh Oct 12 '17 at 17:50
@AnantVikramSingh oh, okay. – EgMusic Oct 13 '17 at 12:18

Not able to open a file using python

1 Answers1