unable to post vales from checkbox in codeigniter

Question

I am developing an application with codeigniter. My issue is iam not able to post value from second check box(checkbox in else condition).

View page

<div class="form-group">             
    <?php if($pro[0]['p_featured']==1){ ?>
     <label class="checkbox-inline">
          <input type="checkbox" value="1" name="featured" checked>featured 
     Product</label><?php } else {?>
    <label class="checkbox-inline">
     <input type="checkbox" value="2" name="featured" >featured 
      Product</label> 
   <?php } ?>
  </div>

My controller

echo $this->input->post('featured'); exit;

I am able to post value from first condition. But not able to POST value from second condition

There is a condition `if($pro[0]['p_featured']==1){` for rendering checkbox, are you sure that your second checkbox is rendering — urfusion, Oct 14 '17 at 05:21
yes I can see the unchecked check box in my form. on inspecting that i can see `` — Yadhu Babu, Oct 14 '17 at 05:24
What you get when you print whole output by `echo "
"; print_r($_POST);` — urfusion, Oct 14 '17 at 05:26
Ok, There is no way that you will not get value of checkbox other then it is not inside the form tag. — urfusion, Oct 14 '17 at 05:31
Let us [continue this discussion in chat](http://chat.stackoverflow.com/rooms/156715/discussion-between-yadhu-babu-and-urfusion). — Yadhu Babu, Oct 14 '17 at 05:40
@urfusion yes but when i change name attribute of second checkbox i am getting value — Yadhu Babu, Oct 14 '17 at 05:43
@YadhuBabu `echo $pro[0]['p_featured']; die;` and post the data — Abdulla Nilam, Oct 14 '17 at 09:06

score 0 · Answer 1 · answered Oct 14 '17 at 07:52

0

try

isset($this->input->post('featured'))?1:2;

answered Oct 14 '17 at 07:52

lochawala

96
4
12

score 0 · Answer 2 · answered Oct 14 '17 at 10:43

Form elements of <input type='checkbox'> will not post a value if not checked. So, if the checkbox is in second condition and it remains unchecked when the form is submitted, then $this->input->post('featured'); will return NULL.

If you were thinking to use the value property to determine which checkbox was output to browser that won't work because value won't be posted if the checkbox is not checked.

Consider this solution

<div class="form-group">             
    <label class="checkbox-inline">
        <input type="checkbox" name="featured" <?php echo $pro[0]['p_featured'] == 1 ? "checked" : NULL; ?>>featured 
        Product</label>
</div>

This produces a checkbox that is checked when $pro[0]['p_featured'] == 1.

Notice the value attribute has been removed. That attribute is not needed in this situation.

When processing the form submit you confirm the state of the checkbox like this

$feature_checked = NULL !== $this->input->post('featured');

The value of $feature_checked will be TRUE if the box is checked, else it will be FALSE.

score 0 · Answer 3 · answered Oct 14 '17 at 13:27

0

<input type="checkbox" id="wifi" name="wi_fi" value="1" <?php if ($post['wi_fi']==1) :?>checked<?php endif;?>/><label for="wifi" >Wi-Fi</label>

answered Oct 14 '17 at 13:27

Mantas Stanislovaitis

73
7

if it will be marked before and it saved in DB, this box will be marked else unmarked :) – Mantas Stanislovaitis Oct 14 '17 at 13:29
It would help if you added some form of explanation for your answer. – Nigel Ren Oct 14 '17 at 20:40

unable to post vales from checkbox in codeigniter

3 Answers3