Trying to match URL using regex

Question

I am trying to match URL using regex

https?:\/\/.*\..*

But unable to understand how to end the match if a space occurs after the URL.

For example in the below Image, for last match, i want it to end, before the space. But nothing seems to be working.

Can you also explain why adding \b (word boundary) at the end doesn't work ?

https://www.regexpal.com/94502 – jmargolisvt Oct 14 '17 at 14:49 — jmargolisvt, Oct 14 '17 at 14:49

score 3 · Answer 1 · answered Oct 14 '17 at 14:50

3

Just use a \S:

https?:\/\/.*\.\S*

\S means: match everything that is not a space char (space, tab, delim..)

answered Oct 14 '17 at 14:50

Neb

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score 1 · Accepted Answer · answered Oct 14 '17 at 14:49

1

Look at the solution below using lazy and a non-capturing group for the last white space:

Look here for far better regex' What is the best regular expression to check if a string is a valid URL?

//well let us dive into this:

var matches = document.querySelector("pre").textContent.match(/https?:\/\/.*\..*/g);

console.log(matches);

/*
your regex does the following
search for http:// or https://
then you want to search for every character that is not a newline until you find a dot
after that you simply search for everything that is not a newline.


you need lazy and a non-capturing group, lazy is ? - (?=\s)
*/

var matches2 = document.querySelector("pre").textContent.match(/https?:\/\/.+?\..+?(?=\s)/g);
console.log(matches2);

<pre>
foo@demo.net

http://foo.co.uk/
http://regexr.com/foo.html?q=bard
https://mediatemple.net jhjhjhjhjhjh
</pre>

answered Oct 14 '17 at 14:49

Mouser

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Because `\b` stops on a word boundery and `.` is a such a boundery. – Mouser Oct 14 '17 at 15:25
isn't space considered as word boundary ? – Ankur Marwaha Oct 14 '17 at 15:27
Yes, but it stops earlier at the first dot. – Mouser Oct 14 '17 at 15:27
https?:\/\/.*\..*\b ---- this is not stopping at . or space in https://regexr.com/ – Ankur Marwaha Oct 14 '17 at 15:29
Because there is no limit to `.*`, try to make it lazy `.*?` – Mouser Oct 14 '17 at 15:29

Trying to match URL using regex

2 Answers2