The best approach is probably to rely on the default copy constructor. For instance, your particular example, which involves a member-wise copy, works fine with the default constructor (i.e., the behavior would be the same even if you simply deleted the constructor). As more members are added, they will automatically receive the same member-wise copy behavior in the default constructor.
In some unusual cases you might want to force the generation of the default constructor (e.g., when you want to have some different, explicitly defined behavior for non-const
source objects). In that case, in C++11 and later, you can explicitly request the default copy constructor as follows:
A(const A&) = default;
Some coding guidelines also recommend always including the above explicit request for the default constructor simply as a form of documentation.
Mostly member-wise, with exceptions
Sometimes, most member of a class are fine with the default member-wise copy, but you have a couple of exceptions. An example would be a raw pointer where you want to perform a deep copy of the underlying data. By default, the pointer is simply copied and so the pointers in the source object and new object will both point to the same location in memory.
The solution is fairly simple: just wrap this pointer and any associated meta-data (e.g., a length field if the pointed to object is an array) in a suitable RAII wrapper whose copy constructor performs the specific non-default behavior you want, and include a member of this type in your class A
. Now A
can continue to use the default copy constructor, which calls your explicit copy constructor for your pointer. Essentially, you are back to the pure member-wise copy, but with the new semantics for your pointer-wrapping member.
This type of matter will also help you keep your destructor and sometimes your constructors trivial as well. No doubt the original class above had some code to delete
your raw pointer. Once wrapped with the copying-RAII wrapper, the wrapper takes care of destruction and so the containing class doesn't have to, and often the destructor can be removed entirely.
This wrapper approach often has zero or close to zero overhead in a language like C++.
You can find some more details in this question.
When that doesn't work
Sometimes the above may not work. One example would be when the copy constructor needs to embed the address (the this
pointer) of the new object in some field. The self-contained wrapper doesn't have a way to get the this
pointer of the containing object (indeed, it doesn't even know it is a member).
One approach here is to create a new sub-object with all of the fields of your original object that use the default copy behavior, and then create your new top level object by aggregating (or by inheritance) this sub-object with the few fields that do need special treatment. Then you can keep the using the default copy constructor for all the fields that should have the default treatment.
This approach can even have performance benefits, since compilers are likely to use a pure memcpy
approach1 for the sub-object, in addition to calling your explicit code for the exceptional fields. When the fields were mingled together in the original object, this is much less likely or impossible (e.g., because the layout of the object may interleave the exceptional fields and default-copied fields).
1 This doesn't actually mean that there will be a call to the standard library memcpy
in the code: for small objects the compiler will usually unroll this for small objects into an unrolled sequence of mostly maximum width loads and stores.