linux shell script: how to compare the value of a script command to an integer

Asked Oct 17 '17 at 05:11

Active Oct 17 '17 at 05:38

Viewed 25 times

For example, I create a shell script number1.sh takes a file as an argument and prints the bytes of the file. Now, I have another shell script number2.sh which also takes a file as argument, and in this shell script I have:

#!/bin/bash 7    
fileByte="./number1.sh $1"
if [ "$fileByte" -eq 0 ] 
then
.....

I want to compare the print result of the command ./number1.sh $1 to the integer 0, but in this case "$fileByte" is ./number1.sh, how should I proceed?

edited Oct 17 '17 at 05:38

SherylHohman

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asked Oct 17 '17 at 05:11

Ciel Yang

1

It's not clear what you are asking. Please include your code to make it clear. Please see: [How to create a Minimal, Complete, and Verifiable example](https://stackoverflow.com/help/mcve). – codeforester Oct 17 '17 at 05:13
for number1.sh #!/bin/bash wc -c $1 – Ciel Yang Oct 17 '17 at 05:19
for number2.sh #!/bin/bash fileByte="./number1.sh $1" if [ "$fileByte" - eq 0] then do ...... – Ciel Yang Oct 17 '17 at 05:21
./number1.sh filename will print a value, I just want to compare this value to 0 in number2.sh in the if statement – Ciel Yang Oct 17 '17 at 05:22
`fileByte=$(./number1.sh $1)` – OmnipotentEntity Oct 17 '17 at 05:26
Thanks!! This works for me! – Ciel Yang Oct 17 '17 at 05:44

linux shell script: how to compare the value of a script command to an integer

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