if statement and printing in python

Question

i dont know why this code not printing 'got it' when i run it it just shows me the prints the else statement , even if the answer is correct.

import random as rand
print('Welcome to the guessing game!')
print('type a number between 1 to 9')
running = True
while running:
    value = rand.randint(1, 9)
    user_guess = input()

    if user_guess == value:
        print('got it')
    else:
        print('not at all')

even ive tried with printing the value to make sure my answer is correct.

`str != int`, it never will... you will need to convert `user_guess` to `int` — Taku, Oct 20 '17 at 14:57
Possible duplicate of [How can I read inputs as integers?](https://stackoverflow.com/questions/20449427/how-can-i-read-inputs-as-integers) — Mel, Oct 20 '17 at 14:57
Also see https://stackoverflow.com/questions/23294658/asking-the-user-for-input-until-they-give-a-valid-response — PM 2Ring, Oct 20 '17 at 15:04

kvorobiev · Accepted Answer · 2017-10-20T18:02:39.123

0

Because after

user_guess = input()

user_guess will be a str and value is an int.
At statement if user_guess == value: you trying to compare str with int.
Try

user_guess = int(input())

edited Oct 20 '17 at 18:02

answered Oct 20 '17 at 14:57

kvorobiev

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if statement and printing in python

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