How to make a program to detect consecutive letters in a QWERTY keyboard layout?

Question

I know this was already asked by other person but i never understood the code and i guess this one is a bit different. So i need a code in my python program that removes 5 points from the variable "points". For example: if password is qwert123 then there are 3 combinations "qwe", 'wer',"ert" and 15 points are removed. Please help me, i need it in a simplest language as possible so i could understand it. Thank you a lot!

    user_password = input()
    password = int(len(user_password))

Where's the link to the other persons question? What have you not understood about the answer there? Be specific, "give code" approach isn't helpful on SO. People will help you if you're willing to learn, if you just want the code, hire somebody to write this code for you. — cinnaroll45, Oct 21 '17 at 22:25
I have not tried anything because i have no idea how to code it. — Alim Alim, Oct 21 '17 at 22:29

score 1 · Answer 1 · answered Nov 05 '17 at 17:36

A solution to this problem can be found here.

Adapting it to the problem at hand, the following code will do what you require:

qwertyKeyboard = ['qwertyuiop', 'asdfghjkl', 'zxcvbnm']
user_password = input("enter password")
points = len(user_password)

def chunkstring(string):
    return (string[0+i:3+i] for i in range(0, len(string)))

for chunk in list(chunkstring(user_password)):
    if len(chunk) == 3:
        if chunk in qwertyKeyboard[0] or chunk in qwertyKeyboard[1] or chunk in qwertyKeyboard[2]:
            print(chunk)
            points -= 5

print(points)

The chunkstring function breaks the password up into chunks of characters, which are then checked by the for loop against the qwertyKeyboard list, and deducts 5 points from the points variable for each set three consecutive characters that are found.

How to make a program to detect consecutive letters in a QWERTY keyboard layout?

1 Answers1