I have looked through multiple websites multiple times and no other posts can find specifically what I am looking for.
The general idea is for the program to search through the entire computer, skipping any folders which deny access or in other ways are inaccessible, for a specific file and then return its location. E.g:
def findFile(targetFile):
targetLocation = searchFor(targetFile) in drives.All
OUTPUT:
targetLocation = "D:\SteamLibrary\steamapps\common\Grand Theft Auto V"
OR:
This file exists in two locations:
"D:\SteamLibrary\steamapps\common\Grand Theft Auto V" and "C:\Program Files (x86)\Steam\steamapps\common\Grand Theft Auto V"
Please specify which:
Thanks
NOTE: I have seen the questions/1724693/find-a-file-in-python and it does not answer my problem. I need something which will handle duplicates by asking you to pick which not putting it in an array
import os
target_filename = "GTA 5.exe"
start_folder = "C:/" #It needs to search every drive (C: D: E: F: etc)
for root, dirs, files in os.walk(start_folder):
if target_filename in files:
print(root + '\\' + target_filename )
output looks like this:
Python 3.6.3 (v3.6.3:2c5fed8, Oct 3 2017, 17:26:49) [MSC v.1900 32 bit (Intel)] on win32
Type "copyright", "credits" or "license()" for more information.
>>>
================== RESTART: C:/Users/Redacted/Desktop/test.py ==================
>>>