Exit=("")
Exit=str(input("Do you require another service? "))
if Exit=="Yes" or "Yeah" or "Y" or "yes":
print("Okay")
elif Exit=="No" or "Nah" or "N" or "no":
print("Terminating Program")
else:
print("Terminating Program")
When Exit=No, the Yes path is chosen. Why?
That's because it short-circuits and returns "Yeah" on the first logical evaluation:
>>> False or True or True
True
>>> False or 'exit'
'exit'
>>> bool(False or 'exit')
True
>>>
I recommend doing this:
if Exit.lower() in ('yeah', 'y', 'yes'):
print("okay")
elif Exit.lower() in ('no', 'nah', 'n'):
print ("Terminating Program")
else:
print ("Terminating Program")
You can use x in (a, b, c) in python to check if variable x contains one of the values a, b or c:
Exit=("")
Exit=str(input("Do you require another service? "))
if Exit in ("Yes", "Yeah", "Y", "yes"):
print("Okay")
elif Exit in ("No", "Nah", "N", "no"):
print("Terminating Program")
else:
print("Terminating Program")
its easier to just check the first character in a case insensitive way
if exit.lower().startswith("y"):
print ("OK")
else:
print("adios muchacho")
as to why your existing code does not work see below
if "anything" is always boolean True
if some_condition or True is also always True, regardless of whether some_condition is True or False
