How to make the input loop if requirements aren't met?

Question

So, the Tip_Percentage must be higher than 15, and I want the input to loop if the requirement for it to be over 15 isn't met, how I make that happen?

Meal_Cost = int(input("Meal Cost: $"))
Patrons = int(input("Number of Patrons: "))
Tip_Percentage = int(input("Tip %: "))

while Tip_Percentage <= 15:
    print("Please give a higher tip than that.")
    break

else:
  if Tip_Percentage >= 15:
    print('\n')


  Price_of_Meal = Meal_Cost / Patrons
  print("Price of Meal: $", Price_of_Meal,)


  Tip_Amount = (Tip_Percentage / 100 * Meal_Cost)
  print("Tip: $", Tip_Amount)

score 1 · Accepted Answer · answered Oct 25 '17 at 23:40

1

Ask for the Tip_Percentage input again:

Tip_Percentage = int(input("Tip %: "))

while Tip_Percentage <= 15:
    print("Please give a higher tip than that.")
    Tip_Percentage = int(input("Tip %: "))

answered Oct 25 '17 at 23:40

TerryA

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score 0 · Answer 2 · answered Oct 25 '17 at 23:41

You need to ask for the tip until it has been greater than or equal to 15.

Meal_Cost = int(input("Meal Cost: $"))
Patrons = int(input("Number of Patrons: "))
Tip_Percentage = int(input("Tip %: "))

while Tip_Percentage <= 15:
    Tip_Percentage = int(input("Please give a higher tip than that : "))

Price_of_Meal = Meal_Cost / Patrons
print("Price of Meal: $", Price_of_Meal,)


Tip_Amount = (Tip_Percentage / 100 * Meal_Cost)
print("Tip: $", Tip_Amount)

How to make the input loop if requirements aren't met?

2 Answers2