How to find out whether a string include digit(s)

Question

How do I find out whether a string has digit(s). For example, "Te6st1" has digits (6 and 1).

Answer 1

You can use re.findall:

>>> re.findall(r'\d+', "Te6st1")
['6', '1']

If you want them as integers, you can then call int on the result:

>>> [int(n) for n in re.findall(r'\d+', "Te6st1")]
[6, 1]

Answer 2

You can use the isdigit() function with something like this

>>> s = "Te6st1"
>>> results = [(char,char.isdigit()) for char in s]
>>> results
[('T', False), ('e', False), ('5', True), ('s', False), ('t', False), ('1', True)]

You can also use the filter operator to get all the digits

>>> digits = filter(lambda x:x.isdigit(), s)
>>> digits
'51'

Hope it helps