Removing Element from Lists of List. PYTHON

Question

for i in file:
   file = [i.strip() for i in file]
return [file[i:i+1] for i in range(0, len(file),1)]

OUTPUT:

[['1,3,4,5,2'], ['4,2,5,3,1'], ['1,3,2,5,4'], ['1,2,4,3,5'], ['1,3,4,5,2'], ['2,1,3,5,4'], ['1,3,4,5,2'], ['3,5,2,4,1'], ['1,4,5,2,3'], ['5,1,4,3,2'], ['3,2,5,4,1'], ['3,1,2,5,4'], ['2,5,1,4,3'], ['3,2,1,4,5'], ['4,5,3,1,2'], ['1,5,4,3,2'], ['1,5,3,4,2'], ['2,1,4,3,5'], ['4,1,2,5,3']]

This is my List with sub-lists.

How can I take off the ' '? So ['1,3,4,5,2'] -> [1,3,4,5,2]

Thanks! (:

Welcome to SO. Please take the time to read [ask] and the links it contains. — wwii, Oct 27 '17 at 01:58
Possible duplicate of [Making a flat list out of list of lists in Python](https://stackoverflow.com/questions/952914/making-a-flat-list-out-of-list-of-lists-in-python) — Jeff Bootsholz, Oct 27 '17 at 02:16

score 0 · Answer 1 · answered Oct 27 '17 at 01:57

You can try this:

s = [['1,3,4,5,2'], ['4,2,5,3,1'], ['1,3,2,5,4'], ['1,2,4,3,5'], ['1,3,4,5,2'], ['2,1,3,5,4'], ['1,3,4,5,2'], ['3,5,2,4,1'], ['1,4,5,2,3'], ['5,1,4,3,2'], ['3,2,5,4,1'], ['3,1,2,5,4'], ['2,5,1,4,3'], ['3,2,1,4,5'], ['4,5,3,1,2'], ['1,5,4,3,2'], ['1,5,3,4,2'], ['2,1,4,3,5'], ['4,1,2,5,3']]
final_data = [map(int, i[0].split(",")) for i in s]

Output:

[[1, 3, 4, 5, 2], [4, 2, 5, 3, 1], [1, 3, 2, 5, 4], [1, 2, 4, 3, 5], [1, 3, 4, 5, 2], [2, 1, 3, 5, 4], [1, 3, 4, 5, 2], [3, 5, 2, 4, 1], [1, 4, 5, 2, 3], [5, 1, 4, 3, 2], [3, 2, 5, 4, 1], [3, 1, 2, 5, 4], [2, 5, 1, 4, 3], [3, 2, 1, 4, 5], [4, 5, 3, 1, 2], [1, 5, 4, 3, 2], [1, 5, 3, 4, 2], [2, 1, 4, 3, 5], [4, 1, 2, 5, 3]]

Simon Mengong · Answer 2 · 2017-10-27T02:15:41.407

try this:

import ast
l = []
s = [['1,3,4,5,2'], ['4,2,5,3,1'], ['1,3,2,5,4'], ['1,2,4,3,5'], ['1,3,4,5,2'], ['2,1,3,5,4'], ['1,3,4,5,2'], ['3,5,2,4,1'], ['1,4,5,2,3'], ['5,1,4,3,2'], ['3,2,5,4,1'], ['3,1,2,5,4'], ['2,5,1,4,3'], ['3,2,1,4,5'], ['4,5,3,1,2'], ['1,5,4,3,2'], ['1,5,3,4,2'], ['2,1,4,3,5'], ['4,1,2,5,3']]
for li in s:
   l.append(list(ast.literal_eval(li[0])))

note: ast is a built-in (standard) module if you don't know it, it cames with python installation

score 0 · Answer 3 · answered Oct 27 '17 at 03:39

One line solution :

list_1=[['1,3,4,5,2'], ['4,2,5,3,1'], ['1,3,2,5,4'], ['1,2,4,3,5'], ['1,3,4,5,2'], ['2,1,3,5,4'], ['1,3,4,5,2'], ['3,5,2,4,1'], ['1,4,5,2,3'], ['5,1,4,3,2'], ['3,2,5,4,1'], ['3,1,2,5,4'], ['2,5,1,4,3'], ['3,2,1,4,5'], ['4,5,3,1,2'], ['1,5,4,3,2'], ['1,5,3,4,2'], ['2,1,4,3,5'], ['4,1,2,5,3']]




print([[int(item_3) for item_3 in item_1 if item_3.isdigit()] for item in list_1 for item_1 in item])

output:

[[1, 3, 4, 5, 2], [4, 2, 5, 3, 1], [1, 3, 2, 5, 4], [1, 2, 4, 3, 5], [1, 3, 4, 5, 2], [2, 1, 3, 5, 4], [1, 3, 4, 5, 2], [3, 5, 2, 4, 1], [1, 4, 5, 2, 3], [5, 1, 4, 3, 2], [3, 2, 5, 4, 1], [3, 1, 2, 5, 4], [2, 5, 1, 4, 3], [3, 2, 1, 4, 5], [4, 5, 3, 1, 2], [1, 5, 4, 3, 2], [1, 5, 3, 4, 2], [2, 1, 4, 3, 5], [4, 1, 2, 5, 3]]

in detailed :

for item in list_1:
    for item_1 in item:
        new=[]
        for item_3 in item_1:
            if item_3.isdigit():
                new.append(int(item_3))
        print(new)

Removing Element from Lists of List. PYTHON

3 Answers3