Why do we get 1 as remainder on the second println?

Question

package PracticePackage;

public class whileLoop {

    public static void main(String[] args) {

        int i=1;

        System.out.println("Quotient "+i/2);    
        System.out.println("Remainder "+i%2);

    }

}

Answer 1

because integers are not real numbers so you get 1 as answer and the real part of remainder is ignored since you defined i as an integer

Answer 2

this is the fomula that Java uses to yield the remainder of its operands:

(a/b)*b+(a%b)

where a is the dividend and b is the divisor.

so in your case it's like:

int i = 1; 
int b = 2;
int result = (i / b) * b + (i % b);

hence the result 1 rather than 0

Answer 3

1/2 = 0.5

you defined i as int

Integral division in java takes floor of the answer if the answer is a real number so 1/2 becomes 0, making 1%2 equal to 1

I hope that explains.