Unterminated object at character 29

Asked Oct 28 '17 at 18:33

Active Oct 28 '17 at 22:11

Viewed 158 times

Trying to decode json from fcm when there are no slashes on the json value it works by not with a slash. Below is the json composition part from the php script

This works

$body="d";
$path="www.google.com";
$msg = array('body'=>$body,'path'=>$path);

This Doesnt

$body="d";
$path="www.google.com/images";
$msg = array('body'=>$body,'path'=>$path);

Json outupt from php script that doesnt works

{"data":{"body":"d","path":"www.google.com\/images"},"to":"\/topics\/test"}

App Try Block

try {
JSONObject json = new JSONObject(remoteMessage.getData().toString());

Log.e(TAG, "Data Payload: " + json.get("body"));
                                   newmessafe(json.get("body").toString(),json.getString("path").toString());

} catch (Exception e) {

Log.e(TAG, "Exception: " + e.getMessage());
}

edited Oct 28 '17 at 22:11

asked Oct 28 '17 at 18:33

dreamer1989

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i get this error Unterminated object at character 29 – dreamer1989 Oct 28 '17 at 22:03
There's a `}` missing at the end. – Nisse Engström Oct 28 '17 at 22:08
Updated. if i there are no / in the path filed no exception is raised – dreamer1989 Oct 28 '17 at 22:13
Thats because the "\" character isnt needed infront of the "/" or it will create "www.google.comimages" instead of "www.google.com/images" – Ellisan Oct 28 '17 at 22:21
@Ellisan "\" gets added to the url after i have encoed it into json from a php array – dreamer1989 Oct 28 '17 at 22:33
what about [this](https://stackoverflow.com/questions/14209052/how-remove-the-backslash-in-the-json-response-using-php) – Ellisan Oct 28 '17 at 22:37
@Ellisan the exception is raised when i try to parse json see the try block above. In the json that i get url is stuctured correctly like www.google.com/images – dreamer1989 Oct 28 '17 at 23:42

Unterminated object at character 29

0 Answers0