Deserializing the JSON in C#

Question

I am having the JSON object which is stored in to in to the Variable. The JSON looks like

{
 "data":
[
{"SNumber":"05",
 "LName":"TyJ",
 "LNameMarkup":"18/TyJ"
}]}

I created the Model class for the JSON like

namespace SetName.Models
{
public class SNameDTO
{     
 public class Datum
 {
  public string SNumber { get; set; }
  public string LName { get; set; }
  public string LNameMarkup { get; set; }
 }

 public class RootObject
 {
  public List<Datum> data { get; set; }
 }
 }
 }

Now I want to deserialize this JSON I can get the LName from it

  var retSName = GetSName(StockNumber);   //stores the JSON shown above

I replaced the above code with

  SNameDTO.RootObject retSName = GetSName(StockNumber);

It throws error like

Cannot implicitly convert type 'string' to 'SetName.Models.SNameDTO.RootObject'

I am trying to use the Model Class instead of the dynamic objects.

Possible duplicate of [Deserialize JSON into C# dynamic object?](https://stackoverflow.com/questions/3142495/deserialize-json-into-c-sharp-dynamic-object) — newfurniturey, Oct 30 '17 at 17:19
@RenatoAfonso that is the method that returns me the JSON I posted above. — xyz, Oct 30 '17 at 17:19
@newfurniturey that uses the dynamic Objects. I am seeing if I can use the Model class. If I can use the Model class how can I approach this — xyz, Oct 30 '17 at 17:23
You are not deserializing anything, your just trying to dump a string (your JSON is a string) into a model, and that won't work. — oerkelens, Oct 30 '17 at 17:25
@oerkelens I am new to this not sure how to use Model class deserializing the JSON variable — xyz, Oct 30 '17 at 17:27

score 1 · Answer 1 · answered Oct 30 '17 at 17:27

1

To actually deserialize your JSON string, you need to do a bit more. If you use Json.Net (available on NuGet) you can try something like:

var myClass = JsonConvert.DeserializeObject<RootObject>(GetSName(StockNumber));

answered Oct 30 '17 at 17:27

oerkelens

5,053
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29

How do I access the LName from the RootObject – xyz Oct 30 '17 at 17:30
@xyz That is a property you have defined yourself... how about `myClass.data.First().Lname` if you want the Lname of the first data object in your list? That has little to do with json or (de)serialization. I suggest you first check in debug if your deserialization works. – oerkelens Oct 30 '17 at 17:33

score 0 · Answer 2 · answered Oct 30 '17 at 17:40

Used Newtonsoft JSON nuget package, able to Deserialize it as below, Hope this helps.

class Program
{
    static void Main(string[] args)
    {
        var json = "{\"SNumber\":\"05\",\"LName\":\"TyJ\",\"LNameMarkup\":\"18/TyJ\"}";

        var jsonCollection =
            "[{\"SNumber\":\"05\",\"LName\":\"TyJ\",\"LNameMarkup\":\"18/TyJ\"},\r\n{\"SNumber\":\"10\",\"LName\":\"TyJ2\",\"LNameMarkup\":\"20/TyJ\"}]";

        var jsonRootObject = "{ \"data\" : [{\"SNumber\":\"05\",\"LName\":\"TyJ\",\"LNameMarkup\":\"18/TyJ\"}, {\"SNumber\":\"10\",\"LName\":\"TyJ2\",\"LNameMarkup\":\"20/TyJ\"}]}";

        var data = JsonConvert.DeserializeObject<SNameDTO.Datum>(json);
        var dataCollection = JsonConvert.DeserializeObject<List<SNameDTO.Datum>>(jsonCollection);
        var rootObject = JsonConvert.DeserializeObject<SNameDTO.RootObject>(jsonRootObject);
    }
}


public class SNameDTO
{
    public class Datum
    {
        public string SNumber { get; set; }
        public string LName { get; set; }
        public string LNameMarkup { get; set; }
    }

    public class RootObject
    {
        public List<Datum> data { get; set; }
    }
}

If you don't want to install additional packages, the .NET JavaScriptSerializer works perferctly on JSON objects. JavaScriptSerializer.Deserialize() method converts your JSON to an object of any type. Just add a reference to the System.Web.Extensions assembly. — Alex X., Oct 30 '17 at 17:50

Deserializing the JSON in C#

2 Answers2