Process a request after GET response Flask

Question

def get(self, name):
    //accept the parameters and parse the parameters
    //genereate UUID
    return{UUID : 'request accepted'}, 200 if item else 404
    generate_doc(parameters, UUID)
   //process the request after the return happens with the parameters from GET

I need to do something like this. I have to call a functions which does something after the response to the GET request is made. I want to do this because the file that I am trying to create is taking sometime. So I want to send the request first and then generate the file.

I don't have any control on the program flow once the app starts running. Can someone help me to solve this issue.

I am using Celery. It is so simple and easy to use. – Tsubaki007 Oct 31 '17 at 17:10 — Tsubaki007, Oct 31 '17 at 17:10

score -1 · Answer 1 · answered Oct 31 '17 at 13:43

-1

Create a job scheduler class. Add a method queue jobs. Call this method to queue the job. Now call this method whenever you want to make a request.

Run the scheduler in the background to complete the jobs in the added queue.

answered Oct 31 '17 at 13:43

Phaneeth

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Process a request after GET response Flask

1 Answers1