I have a list,
numbers=["one","two","three","one","one"]
when I am doing,
numbers.remove("one")
it returns
["two","three","one","one"]
but I want to remove it completely,
My expected output is,
output=["two","three"]
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Pyd
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1There is similar question discussion about this. See https://stackoverflow.com/questions/1157106/remove-all-occurrences-of-a-value-from-a-list – liteC Nov 01 '17 at 06:49
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yes, that's a classic duplicate, thanks. – Jean-François Fabre Nov 01 '17 at 06:51
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ok, Do I need to remove the question ? – Pyd Nov 01 '17 at 07:18
2 Answers
1
Try this:
numbers = ["one", "two", "three", "one", "one"]
[element for element in numbers if element != "one"]
=> ["two", "three"]
We used a list comprehension for doing the job, check the link for details. But basically - we created a new list, filtering out the undesired element via a condition.
Óscar López
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How about a list comprehension
[i for i in numbers if i!="one"]
You can also use a filter (Python 2.x)
filter(lambda x: x!="one",numbers)
Output:
['two', 'three']
Miraj50
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