JQuery Array , 1 issues

Asked Nov 03 '17 at 13:21

Active Nov 04 '17 at 12:17

Viewed 34 times

for (i = 0, j = menuButtonArray.length; i < j; i += 1){
$(menuButtonArray[i]).find("img").attr('src', 'menuImages/'+heavanArray[i]) 
console.log("LOOP = "+i);
}

I am swaping out 9 images. Why doesn't the loop update the array element selector each time. It only works on first loop [0] but will not update, while console log does update.

edited Nov 04 '17 at 12:17

asked Nov 03 '17 at 13:21

Steve van Gelder

You haven't initialised any of the arrays – Master Yoda Nov 03 '17 at 13:22
The `fadeOut` call back runs when the fadeOut has completed which is *after* the loop has completed. – freedomn-m Nov 03 '17 at 13:43
Thanks. I remedied that. I am still having the simple problem that it is not recognizing with the i variable: arrayItem[i] . But if I pot in a real number – Steve van Gelder Nov 03 '17 at 15:25

JQuery Array , 1 issues

0 Answers0