Simplifying lists in python?

Question

I'm new to coding, and am wondering if there is a way to simplify this:

if "!" in name or "$" in name or "%" in name or "^" in name or "&" in name or "*" in name or "(" in name or ")" in name or "_" in name or "-" in name or "+" in name or "=" in name:
points = points + 1

Thank you

`if any(c in name for c in '!$%^'): ...`. (I didn't type out all the characters for brevity) — mgilson, Nov 04 '17 at 20:55
@mgilson If you wanted brevity, you would've added those few chars instead of adding "(I didn't type out all the characters for brevity)" :-P — Stefan Pochmann, Nov 04 '17 at 21:16
Here is a one-liner based on mgilson: `points += any(c in name for c in "!$%^&*()_-+=")`. This works because: If false: points += 0, True: Points +=1. Thanks to Stefan Pochmann too. — Anton vBR, Nov 04 '17 at 21:27
@StefanPochmann -- Ahh, but you forget the amount of time it takes to cross-reference to make sure that I got them all. — mgilson, Nov 05 '17 at 00:01

Ajax1234 · Accepted Answer · 2017-11-04T21:04:52.870

3

You can use regex:

import re
if re.findall('[\!\$\%\^\&\*\_\-\+\=]', name):
   points += 1

edited Nov 04 '17 at 21:04

answered Nov 04 '17 at 21:00

Ajax1234

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You beat me to the answer. :) – Ashkan Nov 04 '17 at 21:01
@StefanPochmann please see my recent edit – Ajax1234 Nov 04 '17 at 21:05
Yeah, that works. But it's super ugly. There's really only a single character there that needs escaping (or putting it first or last). Also, why `findall` instead of `search`? – Stefan Pochmann Nov 04 '17 at 21:06
Sheesh, in plain old C days we had `strstr` for this kind of stuff. And it was *fun.* – yacc Nov 04 '17 at 21:07
@yacc Huh? `strstr` doesn't do what this is doing... – Stefan Pochmann Nov 04 '17 at 21:09
However, it was fun. :D – yacc Nov 04 '17 at 21:10

Alex Pshenko · Answer 2 · 2017-11-04T21:15:04.413

2

chars = set("!$%^&*()_-+=")

if any((i in chars) for i in string):
  points += 1

edited Nov 04 '17 at 21:15

answered Nov 04 '17 at 20:58

Alex Pshenko

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8

Oops, was meant as a suggestion but became an edit. As int(True/False) evaluates to 1/0 you could go straight to adding the points. +1 – Anton vBR Nov 04 '17 at 21:13
`ctrl c - ctrl v` of @mgilson 's comment and adding a redundant `()` around the boolean statement... – j-i-l Nov 04 '17 at 21:13
@jojo There's no tuple anywhere. – Stefan Pochmann Nov 04 '17 at 21:14
1

Deleted @AntonvBR 's edit, seems like a separate answer, rather then addition to mine – Alex Pshenko Nov 04 '17 at 21:15
That's fine. It wasn't another answer but really just a way of adding the point in one line. int(boolean) evaluates to 0/1. Hence no if-statement needed. False: points += 0, True: Points +=1 – Anton vBR Nov 04 '17 at 21:18
@jojo Don't get it, that's basically what I suggested? :) Anyway.. let's move on! – Anton vBR Nov 04 '17 at 21:24

İhsan Cemil Çiçek · Answer 3 · 2017-11-04T21:12:33.477

1

You can write a simple function to achieve this.

def is_included(characters, sentence):
    for character in characters:
        if character in sentence:
            return True
    return False

As mgilson mention you can use any keyword too. However since you are new to programming I suggest you to learn the algorithms of keywords.

edited Nov 04 '17 at 21:12

answered Nov 04 '17 at 21:03

İhsan Cemil Çiçek

191
12

Upps it should be True and False my baf – İhsan Cemil Çiçek Nov 04 '17 at 21:12

Simplifying lists in python?

3 Answers3