String Replace a word that is between special characters

Question

$text_string = "One One One,One.One OneTwo, Onetwo .Onetwo TwoOne One";

I want to replace the word "One" with "Three" which is alone or between special characters or at the beginning/ending of the string. Have anybody an idea?

The result must be:

$text_string = "Three Three Three,Three.Three OneTwo, Onetwo .Onetwo TwoOne Three";

mrks · Answer 1 · 2017-11-04T22:49:10.580

2

You can use \b to check for word boundaries:

$str = 'One One One,One.One OneTwo, Onetwo .Onetwo';
$replaced = preg_replace('/\bOne\b/', 'Three', $str);
echo $replaced; // Three Three Three,Three.Three OneTwo, Onetwo .Onetwo TwoOne Three

edited Nov 04 '17 at 22:49

answered Nov 04 '17 at 21:22

mrks

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this is case sensitive now? – Em Hi Nov 04 '17 at 21:28
If you want it to be, add an `i` behind the regex: `/\\bOne\\b/i` – mrks Nov 04 '17 at 21:31
why do you put `\\b`, instead of just `\b` - see https://regex101.com/r/O7C3cl/1 – ArtisticPhoenix Nov 04 '17 at 21:34
c'n'p error, thanks – mrks Nov 04 '17 at 22:49
cant replace a word contains Ü,Ä,Ö with this `$returnValue = preg_replace('/\bÜber\b/i', 'Three', 'One Über One,One.Über one OneTwo, Onetwo .Onetwo TwoOne Über', -1);` – Em Hi Nov 23 '17 at 19:33
have it! `setlocale();` – Em Hi Nov 23 '17 at 22:31

String Replace a word that is between special characters

1 Answers1