There is no predefined function in C to remove a given substring from a C string, but you can write one using strstr
and memmove
. Note that if you remove the substring in place, you cannot use memcpy
nor strcpy
because these have undefined behavior if the source and destination arrays overlap.
Here is the code:
#include <string.h>
char *strremove(char *str, const char *sub) {
size_t len = strlen(sub);
if (len > 0) {
char *p = str;
while ((p = strstr(p, sub)) != NULL) {
memmove(p, p + len, strlen(p + len) + 1);
}
}
return str;
}
Note that the resulting string may contain the substring as is the case in your example.
Netherwire suggested an optimisation:
char *strremove(char *str, const char *sub) {
size_t len = strlen(sub);
if (len > 0) {
char *p = str;
size_t size = 0;
while ((p = strstr(p, sub)) != NULL) {
size = (size == 0) ? (p - str) + strlen(p + len) + 1 : size - len;
memmove(p, p + len, size - (p - str));
}
}
return str;
}
Further honing the code, I came up with an even more efficient version using the 2 finger-method: only copying the fragments between matches starting after the first match:
char *strremove(char *str, const char *sub) {
char *p, *q, *r;
if (*sub && (q = r = strstr(str, sub)) != NULL) {
size_t len = strlen(sub);
while ((r = strstr(p = r + len, sub)) != NULL) {
memmove(q, p, r - p);
q += r - p;
}
memmove(q, p, strlen(p) + 1);
}
return str;
}
Here is the same method without any calls to memmove
:
char *strremove(char *str, const char *sub) {
char *p, *q, *r;
if (*sub && (q = r = strstr(str, sub)) != NULL) {
size_t len = strlen(sub);
while ((r = strstr(p = r + len, sub)) != NULL) {
while (p < r)
*q++ = *p++;
}
while ((*q++ = *p++) != '\0')
continue;
}
return str;
}