How do I convert std::numeric_limits::epsilon() in c?

Question

I'm trying to use std::numeric_limits<float>::epsilon() in c.

The description says

Returns the machine epsilon, that is, the difference between 1.0 and the next value representable by the floating-point type T.

How can I represent the identical value in c?

See also: https://stackoverflow.com/questions/11883900/epsilon-for-various-float-values — Antti Haapala -- Слава Україні, Nov 06 '17 at 04:58

score 4 · Accepted Answer · answered Nov 06 '17 at 04:50

4

#include <float.h>

and use

FLT_EPSILON DBL_EPSILON LDBL_EPSILON

answered Nov 06 '17 at 04:50

Brandon

2

My apologies, I was going off of Zack's quoted text, which is "the largest finite value that can be represented by the type", but that's not actually what `std::numeric_limits::epsilon()` is. `FLT_EPSILON` matches that, it just doesn't match the quoted text. – Lily Ballard Nov 06 '17 at 04:53
1

@KevinBallard I'm sorry it was my mistake. I just edited my post. – Zack Lee Nov 06 '17 at 04:56

1 Answers1