Fetch only a part of the filename from path

Question

I have a folder structure like /folder1/folder2/logs/my_sample_log_.txt

I need only my_sample_log

Could anyone of you please help me ? I have been struggling with this.

Which shell are you using? can you print what is under `echo $SHELL` ? — Inian, Nov 06 '17 at 08:06

Indent · Answer 1 · 2017-11-06T08:09:24.997

0

use basename command :

name=$(basename "/folder1/folder2/logs/my_sample_log_.txt" .txt | sed 's/_$//' )

or simply :

name=$(basename "/folder1/folder2/logs/my_sample_log_.txt" _.txt  )

edited Nov 06 '17 at 08:09

answered Nov 06 '17 at 08:06

Indent

1 Answers1