jQuery inArray returning false when needle exists in haystack

Question

I am trying to check if user code exist in array. But the jQuery code is returning false even when the code exist in array.

function isValidCode(code){
  var arr = [1, 2, 3];
  //return ($.inArray(code, arr) > -1);
  return ($.inArray(code, arr) !== -1);
}

function LuckWinner(key){
  if(isValidCode(key)){
    console.log(key+ ": is in array");
  } else {
    console.log(key+" is NOT in array");
  }
}

https://stackoverflow.com/questions/18867599/jquery-inarray-how-to-use-it-right follow this url i think this will help you. — Kuldeep Mishra, Nov 06 '17 at 11:17
@KuldeepMishra i did check the question, but it didn't sove it — Peter, Nov 06 '17 at 11:22

score 2 · Accepted Answer · answered Nov 06 '17 at 11:22

2

Your code seems to be working just as expected.

Note that $.inArray() will perform a type comparison; I expect you are passing a string. If you are testing for a key that is a string, your isValidCode function will return false, as your array only contains integer values. You can cast the code to an integer with parseInt to avoid this issue:

function isValidCode(code){
    var arr = [1, 2, 3];

    return ($.inArray( parseInt( code, 10 ), arr ) !== -1);
}

answered Nov 06 '17 at 11:22

George

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@PhilipJems Glad to have helped. – George Nov 06 '17 at 11:27
@PhilipJems, if this solved the problem please mark as solved – derloopkat Nov 06 '17 at 11:33

jQuery inArray returning false when needle exists in haystack

1 Answers1