How to pass datatable (HTML table with selected dropdown) values to array in PHP?

Question

I need to fetch values of datatable cells having dropdowns that are selected. And pass the value to an array. How can this be done using php, jquery? Share with example

Answer 1

I am noob like you, but I've learned some php mysqli from here (note: always type misqli instead of mysql in your code) https://m.youtube.com/watch?list=PL7lhMROXakvdLAUKFNLYl_J2Ti0Ulr6ID&params=OAFIAVgB&v=dWzzRkxrTMA&mode=NORMAL. And about json: alue into the the input's max attribute. Something like this will do the trick.

window.onload (//or what trigger method you need) = function() {
    var (//name a var) = $('#idOfElementTogetValueFrom').val();
    $.ajax(
    {type: 'post',
    url: 'path to php doc.php',
    dataType: 'json'
    data: {
    NameX: nameOfVar declared above,
},
    success: function (response){
   $('#idOfelementWhereToDisplayphpResponse').html(response.matchthatnameinPhp); 
}
});

}

In your php js variable will be like $_POST['NameX'] (do what you need with it) Then in php echo json_encode array( "matchthatnameinPhp" => any php you need, vars etc.(//this will be displayed in html) (//You can add more rows of datas here) ) See also: Send JSON data from Javascript to PHP?

Answer 2

I got the solution, by saving the data in an array and on submit button passing it to controller