Open image after BytesIO

Asked Nov 07 '17 at 15:32

Active Nov 07 '17 at 15:32

Viewed 454 times

I would like to get a photo from my url. Trying to create it ,then use .get() and convert it into :BytesIO()

 img = Image.fromarray(srcData) 
 fp = 'https://telegram.org/new.png'
 response = requests.get(fp)
 f = BytesIO(response.content)
 f.seek(0)
 f=Image.open(f)

Why do I get an error, which is:

cannot identify image file _io.bytesio

Then try to send it:

bot.send_photo(chat_id=chat_id, photo=f)

asked Nov 07 '17 at 15:32

X21

2

Maybe something from this answer could help https://stackoverflow.com/a/13137873 – Cole Nov 07 '17 at 15:39
to load an image from url, i use this code. https://pastebin.com/raw/5fwUCFJp – Shoaib Zafar Nov 07 '17 at 15:49
@Cole thank you! It helped. But can I ask smth? – X21 Nov 07 '17 at 16:04
@Cole It's a bout a telegram bot... – X21 Nov 07 '17 at 16:21

Open image after BytesIO

0 Answers0