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I am fairly new to C++ and am trying to understand pointers. Why does the following code output asdf instead of the memory address of a? From my understanding, a pointer is a variable that stores a memory address of type, in this case, char. So wouldnt printing p simply print the memory address of the first character?

int main()
{
    char *p="asdf";
    cout<<p;
    return 0;
}
J Lem
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    There's [an overload of `operator<<`](http://en.cppreference.com/w/cpp/io/basic_ostream/operator_ltlt2) taking `const char*` and interpreting it as pointing to a NUL-terminated C-style string (because it's a common thing to want to do). There's [another overload](http://en.cppreference.com/w/cpp/io/basic_ostream/operator_ltlt) taking `void*` and printing the address. Therefore, if it's the address you want, just do `cout << static_cast(p);` – Igor Tandetnik Nov 10 '17 at 02:35
  • cout<

     – Muhammad Shauket Nov 10 '17 at 04:08

0 Answers0