Jquery Ajax not working while using json_encode

Asked Nov 10 '17 at 16:52

Active Nov 10 '17 at 17:04

Viewed 43 times

I am trying to get value from Jquery Ajax, but it is not getting.

The problem is in the below code:

<?php

header('Content-Type: application/json');
if(isset($_GET['od'])){
    $deotd = $_GET['od'];
}
date_default_timezone_set('Asia/Calcutta');
$cdate = date('Y-m-d H:i:s ', time());
$scdate = strtotime($cdate);
$e = $scdate - $deotd;
$f = "2700" - $e;

// You would calculate a real value here
echo json_encode([
  'tleft' => $f
]),
json_encode([
  'diffex' => $e
]);
?>

In deep the problem is with:

echo json_encode([
  'tleft' => $f
]),
json_encode([
  'diffex' => $e
]);

But what is the problem, I am unable to solve it.

edited Nov 10 '17 at 16:56

Chirag Jain

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asked Nov 10 '17 at 16:52

MKJ

1

Where's your ajax? – Kisaragi Nov 10 '17 at 16:55
`echo json_encode(['tleft' => $f]), json_encode([ 'diffex' => $e]);` You're calling `json_encode` twice, and the second time as a second argument of the first. You should combine them into one array and call `json_encode` only once – Machavity Nov 10 '17 at 16:56
try to echo only one json you can have both keys and values in there – john Smith Nov 10 '17 at 16:56
@johnSmith How? – MKJ Nov 10 '17 at 16:57
@Machavity How? – MKJ Nov 10 '17 at 16:58
1

@MKJ `echo json_encode([ 'tleft' => $f, 'diffex' => $e ]);` – john Smith Nov 10 '17 at 17:01
@MKJ You really need to read the manual on this one. This is a fundamental of how PHP works http://php.net/manual/en/language.types.array.php – Machavity Nov 10 '17 at 17:02
@Machavity Dont think its a duplicate, the question is just not asked good. Think He/She wants to parse the data on the javascript side – john Smith Nov 10 '17 at 17:03
@johnSmith Yeah, I picked the wrong one. I finally chased down the proper dupe and fixed it – Machavity Nov 10 '17 at 17:05

Jquery Ajax not working while using json_encode

0 Answers0